Question

Chapter 27, Problem 044 In the figure R1 = 1302, R2 = R3 = 44.0 2, R4 = 1042, and the ideal battery has emf ε = 6.00 V. (a) What is the equivalent resistance? What is i in (b) resistance 1, (c) resistance 2, (d) resistance 3, and (e) resistance 4? R RA RA (a) Number Units (b) Number Units (c) Number Units V (d) Number Units (e) Number Units

Answer 1

RI IRI pur + Inst t. E R3 R23 R3 R3 E = 6V, is + Tox) 104 104 = 18.22 cererit, R= I = 12 +2.11 Ri= 1302., R2 = R3 =496 RA = 1042, (aj a equivalent resistance between R2 R3 and Ra Bi a pre tento the f*** tra ( a to 104X22 109+22 R' = 18.22 Now equivalent restance of the total (R't Ri) = (12€ +18.2012 = 148.22 R = 148.22 cument in the resistance Ri, (The Amp 148.2 5x10-3 Amp I = 40.5mA. so, corrent in Ra is 40.5 mA that the voltages R2, Rz and Rq are same. I, R2 Iz Rq or fi R2 = (1-211) Rq I R2 = IR4-21, R4 (I Rq (40.5 X 104) mA R2+284) 14+ (2x104) Ip = ({- 21.) = $10.5-2267 om my 2 mA. arment in resistance 27 16.7 mA (d) Comment in resistance of Ž 16.7 mA (e) 4 ra 6. E/R = 40.5 from the concent, we can say so, = मा = - 1) 1 12 7.1 m A