a) for the net resistance
Rnet = R1 + 1/(1/R2 + 1/R3 + 1/R4)
Rnet = 110 + 1/(1/67 + 1/67 + 1/87.9)
Rnet = 134.3 Ohm
the net resistance is 134.3 Ohm
b) for the current in R1
i1 = E/Req
i1 = 6/134.3
i1 = 0.0447 A
the current i1 is 0.0447 A
c)
for the voltage across R2
V2 = 6 - 0.0447 * 110 = 1.08 V
for the current in resistance R2
current in R2 = 1.08/67
current in R2 = 0.016 A
d)
current in R3 = 1.08/67
current in R3 = 0.016 A
e)
current in R4 = 1.08/87.9
current in R4 = 0.0123 A
Chapter 27 Problem 044 GO In the figure R 110 0, Rz-R3-67.0 9, RA 87.9 0,...
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