Question

2501 b) 254 g c) 266 g 270 g e) 286 g Pls PT 3 PI 3 0.6567 m Y O.985 PI 3 e 0-656X 4111621/mol 970.33 Yield is 98.S 970-33x . Jrang The reaction of 5.0 g of F2 with excess Cl2 produced 5.6g of CIF3. What is the percent yield of the reaction?F2 38.00 g/mol, CIF3 = 92.45 g/mol Cl2+3F2 2CIF a) 92% b) 58% c) 69% d) 76% e) 86% For questions 9-12, use the following equation SiO2= 60.09 g/mol, HF = 20.01 g/mol, SiF= 104.09 g/mol, H2O = 18.02 g/mol

Answer 1

Cl2 + 3 F2 - 2 cl F3 mol F2 = 5.0 38 - -- 0.13/mol Cl2 = excen. mol CF3 = 2/6 x 0.131 - 0.0877 ml mass el Fz - 0.0877 X 92.45 T 8. 107 9 m to Sild - 5 x 100 = 69%