Following is the ordered data set and calculations for mean and SD:
Sample size: n=33
(a)
The 10th percentile will be
Since 3rd data value is 13 and 4th data value is 14 so required percentile is
--------------------
The 90th percentile will be
Since 30th data value is 38 and 31st data value is 39 so required percentile is
b)
Mean:
c)
Standard deviation:
Confidence interval:
d)
Out of 33 data values, 16 are less than equal to 25 so required fraction is
Confidence interval:
e)
The critical value for one sided confidence interval is
The one sided confidence interval for mean is
The one sided confidence interval is (-infinity, 29.08).
i need help with the question 13.2 13.2 Answer the following for the data of Exercise...
For the following two datasets labeled y1 and y2 match one quantity in column A with one quantity in column B. The sample means and variances are labeled as y1, y2, S12 and S22. The population means and variances from which they were drawn are labeled μ1,μ2, σ12, and σ22. Assume that the two samples are independent random samples. H0: μ1=μ2 against the alternative Ha: μ1≠μ2 using significance level α=.01. Using the data from problem 1 provide the following information...
1. Consider the following sample spot speed data. The speeds are in miles per hour Speed Grou Lower Limit Upper Limit Mid-point Frequenc 27.5 32.5 37.5 42.5 47.5 52.5 57.5 62.5 67.5 72.5 77.5 82.5 87.5 92.5 25 30 35 40 45 50 22.6 27.6 32.6 37.6 42.6 47.6 52.6 57.6 62.6 67.6 72.6 77.6 82.6 87.6 2 14 25 60 65 70 75 80 85 90 4 (a) Calculate the sample mean speed (b) Calculate the sample median speed...
Question 1: Alex was studying how far the University students travelled to take the class on campus. Let W be the distance travelled (measured in miles). This time, a sample of size 50 was collected. He calculated the following statistics based on the sample: Alex wanted to run a hypothesis test with the null and alternative hypothesis as below: Note that is the mean distance travelled by University students to come to campus. Please calculate the test statistic for the...
I need the completed and correct answer asap. thank you A 95% confidence interval for a population mean is from 101 to 104. What can we conclude from this? For 95% of all possible samples from this population, the confidence interval calculation will produce an interval contaming the population mean, so, based on this sample, we believe the population mean is between 101 and 104 The population mean is between 101 and 104 95% of all possible samples from this...
(10 pts) Use the following information for all parts: On a particular golf course, a sample of 40 golfers have a mean golf score of 79. Suppose the population standard deviation for this course is 3.6605. (a) Using the formula a 90% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter where x is any number, type sqrt(x). For example, should be typed as...
I need help with calculating L and n for the following problem in principal curvature we have that and i know that but i have problem calculating the answer should be that We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this image1+12 1+12
answer a,b is correct I need help with c,d 3 1a0 poists) The airborne times (ins minates) for United Airlines Flight 448 from Albu guenque to Denver on 64 randomly selected days have the mean 54.2 min and standard deviation 13.5 min (a) Can we conclude the population mean airborne time is less than 1 hour? (b) Construct 90% confidence interval for the population mean airborne time. (e) What is the level of the contidence interval (51.77,5663)7 (d) How many...
.NEED ANSWER ASAP A.) B.) NEED ANSWERS TO A.) and B.) The mean and standard deviation of a random sample of n measurements are equal to 33.8 and 3.7, respectively. a. Find a 95% confidence interval for p if n = 144. b. Find a 95% confidence interval for u if n=576. c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the...
Just need to solve Problem 4 4.2.14. Let X denote the mean of a random sample of size 25 from a gamma-type distribution with a = 4 and 3 > 0. Use the Central Limit Theorem to find an approximate 0.954 confidence interval for pl, the mean of the gamma distribution. Hint: Use the random variable (X - 43)/(432/25)/2 = 5X/23 - 10. 21 TL11C1L We were unable to transcribe this image