Assignment Score: 100/300 Resources Hint Check Answer Check Answer < Question 1 of 3 > Modify...
drawing and explanation please Modify the given fatty acid so that it represents the 18-carbon fatty acil designated 18:2(A912). Draw any double bonds in the cis configuration. Utlizise Groups when appropriate. Select Draw Rings Groups More Erase COOH COO COO
Modify the given fatty acid so that it represents the 18-carbon fatty acid designated 18:2( A the cis configuration. Utlizise Groups when appropriate. 2). Draw any double bonds in Select Draw Rings Groups More Erase
Give Up? Hint Assignment Score: Resources 100/300 Check Answer Question 2 of 3 > The fused-ring steroid nucleus of cholesterol is shown. Add atoms as necessary to show the entire structure of cholesterol. Select Rings Draw More Erase C H !!!
Modify this 18-carbon fatty acid so that it becomes an omega-3 (0-3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. Select Draw Rings More Erase 2
Modify this 18-carbon fatty acid so that it becomes an omega-3 (?–3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. Modify this 18-carbon fatty acid so that it becomes an omega-3 (-3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. COO
Assignment Score: Resources 400/1100 Hint Check Answer Question 3,of 11 Draw 3-ethylhexanoic acid. Draw the structure in line-bond form. Erase More Draw Rings Select H
Resources Assignment Score: 100/300 Hint Check Answer < Question 3 of 3 > The elementary reaction 2 H2O(g) 2 H, (g) + 02(g) proceeds at a certain temperature until the partial pressures of H,O, H,, and O, reach 0.0750 atm, 0.00450 atm, and 0.00800 atm, respectively. What is the value of the equilibrium constant at this temperature? Кр -
< Assignment Score: 600/1100 Resources Hint Check Answer Question 9 of 11 > 0/100 Complete the ionization reaction of butanoic acid (CH,CH,CH,COOH) in water. Include all hydrogen atoms and charges 00/100 Correct Select Draw Rings More Erase 0/100 // M CO 100/100 Correct + H, 100/100 Correct H,C-CH-CH2---0---OH *H OH 100/100 Correct 0/100 0/100 O100
Modify the given fatty acid so that it represents the 18-carbon fatty acid designated 18:21A%.12). Draw any double bonds ir the cis configuration. Utlizise Groups when appropriate. Select Draw Rings Groups More mm
drawing and explanation please Modify this 18-carbon fatty acid so that it becomes an omega-6 (o-6) fatty acid designated as 18:2. Add a double bond that is in the cis configuration. Erase Select Draw Rings More H