1 year= $5,000
2 year=$5,000
3 year= $8,000
4 year= $11,000
5 year= $14,000
6 year= 17,000
Homework Answers
NPW = 20000 - 5000 * (P/A,13%,6) - 3000 * (P/G, 13%,5)*(P/F, 13%,1)
= 20000 - 5000 * 3.9975 - 3000 * 6.1802*0.8850
= -16395.93
EUAW = -16395.93 *(A/P, 13%,6)
= -16395.93 * 0.2502
= -4102.26 ~ -4102 (Round to nearst Dollar)
Add Answer to:
1 year= $5,000
2 year=$5,000
3 year= $8,000
4 year= $11,000
5 year= $14,000
6 year=...
Problem 6-2 (book/static) Question Help Years SS.OCC $6,000 58.000 511000 s14000 517000 Click the icon to...
Problem 6-2 (book/static) Question Help Years SS.OCC $6,000 58.000 511000 s14000 517000 Click the icon to view the interest factors for discrete compounding when i = 13% per year. i More Info The equivalent annual worth is $ . (Round to the nearest doller.) Single Payment Equal Payment Series Gradient Series N Compound Amount Factor (F/P, I, N) 1.1300 1.2769 1.4429 1.6305 1.8424 Present Worth Factor (P/F, I, NJ 0.8850 0.7831 0.6931 0.6133 0.5428 Compound Amount Factor (F/A,,N) 1.0000 2.1300...
For an interest rate of 13% compounded annually, determine the following (a) How much can be...
For an interest rate of 13% compounded annually, determine the following (a) How much can be lent now if $18,000 will be repaid at the end of four years? (b) How much will be required in six years to repay a $26,000 loan received now? Click the icon to view the interest factors for discrete compounding when ,-13% per year (a) The amount to be lent now is $ . (Round to the nearest dollar) More Info Compound Present Worth...
Use the imputed market value technique to determine the better alternative below. The MARR is 13%...
Use the imputed market value technique to determine the better alternative below. The MARR is 13% per year and the study period is six years. Capital Investment, millions Annual Expenses, millions Useful Life, years Market Value (End of useful life) Alternative J 41 11 6 0 Alternative K 66 18 10 0 Click the icon to view the interest and annuity table for discrete compounding when the MARR is 13% per year. The present worth of Alternative J over six...
A firm has decided to manufacture biodegradable golf tees. These are two production processes av...
A firm has decided to manufacture
biodegradable golf tees. These are two production processes
available for consideration.
Assuming material and direct labor costs are the only variable
costs and the
MARRequals=1313 %
per year, over what range of annual production volume is Process
A preferred. Assume repeatability.
& Problem 6-33 (algorithmic) Question Help A firm has decided to manufacture biodegradable golf tees. These are two production processes available for consideration. Assuming mater al and direct labor costs are the only...
Suppose that you have an old car that is a real gas guzzler. It is 10...
Suppose that you have an old car that is a real gas guzzler. It is 10 years old and could be sold to a local dealer for $500 cash. The annual maintenance costs will average $800 per year into the foreseeable future, and the car averages only 10 miles per gallon. Gasoline costs $3.40 per gallon, and you drive 17,000 miles per year. You now have an opportunity to replace the old car with a better one that costs $6,000....
Please Calculate the expected PW value for building and widening a two-lane bridge. Will rate highly....
Please Calculate the expected PW value for building and widening
a two-lane bridge. Will rate highly.
A bridge is to be constructed now as part of a new road. An analysis has shown that traffic density on the new road will justify a two-lane bridge at the present time. Because of uncertainty regarding future use of the road, the time at which an extra two lanes will be required is currently being studied. The estimated probabilities of having to widen...
1 year= $3000 2 year= $3000 3 year= $6000 4 year= $9000 5 year= $12000 6 year= $15000 X Problem 6-2 (algorithmic) Questi...
1 year= $3000
2 year= $3000
3 year= $6000
4 year= $9000
5 year= $12000
6 year= $15000
X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the icon to view the interest factors for discrete compounding when = 7% per year. i More Info The equivalent annual worth is S . (Round to the nearest dollar) Single Payment Compound Present Amount Worth Factor Factor (F/P.I, NJ (P/F, I, NJ...
X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the i...
X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the icon to view the interest factors for discrete compounding when = 7% per year. i More Info The equivalent annual worth is S . (Round to the nearest dollar) Single Payment Compound Present Amount Worth Factor Factor (F/P.I, NJ (P/F, I, NJ 1.0700 0.9346 1.1449 0.8734 1.2250 0.8163 1.3108 0.7629 1.4028 0.7130 Compound Amount Factor (F/A, i, N) 1.0000 2.0700...
Consider the accompanying cash flow diagram. Compute the equivalent annual worth at i= 10 % 6....
Consider the accompanying cash flow diagram. Compute the equivalent annual worth at i= 10 % 6. $5,000 $6,000 $4,000 $3,000 2 4 56 Years $3,000 Click the icon to view the interest factors for discrete compounding when i 10% per year The equivalent annual worth is $ (Round to the nearest dollar.) 8: More Info Equal Payment Series Single Payment Gradient Series Gradient Present Compound Present Compound Amount Sinking Present Capital Recovery Gradient Worth Fund Worth Uniform Amount Factor Factor...
Consider the cash flow diagram and i = 10%. What is the equivalent annual value? &nbs
Consider the cash flow diagram and i = 10%. What is the
equivalent annual value?
Equal Payment Series Gradient Series Single Payment Compound Present Amount Worth Factor Factor (F/P.IN) (P/EN) Compound Amount Factor (F/A,IN) Sinking Fund Factor (A/EN) Present Worth Factor (P/A.IN) Capital Recovery Factor (A/P.AN) Gradient Uniform Series (A/GIN) Gradient Present Worth (P/G/N) N N 1.1000 1.2100 1.3310 1.4641 1.6105 0.9091 0.8264 0.7513 0.6830 0.6209 1.0000 2.1000 3.3100 4.6410 6.1051 1.0000 0.4762 0.3021 0.2155 0.1638 0.9091...
Problem 6-2 (book/static) Question Help Years SS.OCC $6,000 58.000 511000 s14000 517000 Click the icon to view the interest factors for discrete compounding when i = 13% per year. i More Info The equivalent annual worth is $ . (Round to the nearest doller.) Single Payment Equal Payment Series Gradient Series N Compound Amount Factor (F/P, I, N) 1.1300 1.2769 1.4429 1.6305 1.8424 Present Worth Factor (P/F, I, NJ 0.8850 0.7831 0.6931 0.6133 0.5428 Compound Amount Factor (F/A,,N) 1.0000 2.1300...
For an interest rate of 13% compounded annually, determine the following (a) How much can be lent now if $18,000 will be repaid at the end of four years? (b) How much will be required in six years to repay a $26,000 loan received now? Click the icon to view the interest factors for discrete compounding when ,-13% per year (a) The amount to be lent now is $ . (Round to the nearest dollar) More Info Compound Present Worth...
Use the imputed market value technique to determine the better alternative below. The MARR is 13% per year and the study period is six years. Capital Investment, millions Annual Expenses, millions Useful Life, years Market Value (End of useful life) Alternative J 41 11 6 0 Alternative K 66 18 10 0 Click the icon to view the interest and annuity table for discrete compounding when the MARR is 13% per year. The present worth of Alternative J over six...
A firm has decided to manufacture
biodegradable golf tees. These are two production processes
available for consideration.
Assuming material and direct labor costs are the only variable
costs and the
MARRequals=1313 %
per year, over what range of annual production volume is Process
A preferred. Assume repeatability.
& Problem 6-33 (algorithmic) Question Help A firm has decided to manufacture biodegradable golf tees. These are two production processes available for consideration. Assuming mater al and direct labor costs are the only...
Suppose that you have an old car that is a real gas guzzler. It is 10 years old and could be sold to a local dealer for $500 cash. The annual maintenance costs will average $800 per year into the foreseeable future, and the car averages only 10 miles per gallon. Gasoline costs $3.40 per gallon, and you drive 17,000 miles per year. You now have an opportunity to replace the old car with a better one that costs $6,000....
Please Calculate the expected PW value for building and widening
a two-lane bridge. Will rate highly.
A bridge is to be constructed now as part of a new road. An analysis has shown that traffic density on the new road will justify a two-lane bridge at the present time. Because of uncertainty regarding future use of the road, the time at which an extra two lanes will be required is currently being studied. The estimated probabilities of having to widen...
1 year= $3000
2 year= $3000
3 year= $6000
4 year= $9000
5 year= $12000
6 year= $15000
X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the icon to view the interest factors for discrete compounding when = 7% per year. i More Info The equivalent annual worth is S . (Round to the nearest dollar) Single Payment Compound Present Amount Worth Factor Factor (F/P.I, NJ (P/F, I, NJ...
X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the icon to view the interest factors for discrete compounding when = 7% per year. i More Info The equivalent annual worth is S . (Round to the nearest dollar) Single Payment Compound Present Amount Worth Factor Factor (F/P.I, NJ (P/F, I, NJ 1.0700 0.9346 1.1449 0.8734 1.2250 0.8163 1.3108 0.7629 1.4028 0.7130 Compound Amount Factor (F/A, i, N) 1.0000 2.0700...
Consider the accompanying cash flow diagram. Compute the equivalent annual worth at i= 10 % 6. $5,000 $6,000 $4,000 $3,000 2 4 56 Years $3,000 Click the icon to view the interest factors for discrete compounding when i 10% per year The equivalent annual worth is $ (Round to the nearest dollar.) 8: More Info Equal Payment Series Single Payment Gradient Series Gradient Present Compound Present Compound Amount Sinking Present Capital Recovery Gradient Worth Fund Worth Uniform Amount Factor Factor...
Consider the cash flow diagram and i = 10%. What is the
equivalent annual value?
Equal Payment Series Gradient Series Single Payment Compound Present Amount Worth Factor Factor (F/P.IN) (P/EN) Compound Amount Factor (F/A,IN) Sinking Fund Factor (A/EN) Present Worth Factor (P/A.IN) Capital Recovery Factor (A/P.AN) Gradient Uniform Series (A/GIN) Gradient Present Worth (P/G/N) N N 1.1000 1.2100 1.3310 1.4641 1.6105 0.9091 0.8264 0.7513 0.6830 0.6209 1.0000 2.1000 3.3100 4.6410 6.1051 1.0000 0.4762 0.3021 0.2155 0.1638 0.9091...
Most questions answered within 3 hours.
-
An entomologist discovers a dung beetle rolling a ball of dung
along the ground, and decides...
asked 1 hour ago -
Humans have used horses for transportation for millions of
years. Therefore, they will use horses for...
asked 3 hours ago -
The following are the Jensen Corporation's unit costs of making
and selling an item at a...
asked 3 hours ago -
Does direct Medicare reimbursement of Advanced practice nurses
increase access to their services?
asked 4 hours ago -
List and explain why a company would choose to use a
published
compensation survey vs. creating...
asked 4 hours ago -
A discrete random variable X can take values from 1 to 10. Find
the variance of...
asked 4 hours ago -
The primary financial goal of a corporation is to maximize:
shareholders wealth.
earnings per share.
stock...
asked 5 hours ago -
determine whether the vectors u=(1,2,3,), v=(-2,1,0) and
w=(1,0,1) are linearly dependent or independent.
asked 5 hours ago -
python
Define a function called print_values which takes a dictionary
object as a parameter. The function...
asked 6 hours ago -
In Chapter 1 you created a program named Triangle in
which you displayed a seven-line triangle...
asked 6 hours ago -
Research question: What are the differences between separately
stated and non separately stated transactions in an...
asked 6 hours ago -
By using Arduino write a code that connects two LEDs to two
push-buttons. Each button controls...
asked 7 hours ago