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Dakota | ||||
Calculation of depletion amount in 5 months | Amount $ | Note | ||
Cost of land | 7,228,320.00 | A | ||
Estimated ore available | 9,768,000.00 | B | ||
Depletion cost per ton | 0.74 | C=A/B | ||
Tonnage | 504,000.00 | D | ||
Amount depleted | 372,960.00 | E=C*D | ||
Calculation of depreciation amount in 5 months | Amount $ | |||
Cost of machinery | 488,400.00 | F | ||
Estimated ore available | 9,768,000.00 | See B | ||
Depletion cost per ton | 0.05 | G=B/F | ||
Tonnage | 504,000.00 | See D | ||
Depreciation amount | 25,200.00 | H=G*D | ||
Journal Entry | ||||
Event | Account | Debit $ | Credit $ | |
a. | Mining Land | 7,228,320.00 | See A | |
Cash | 7,228,320.00 | |||
b. | Machinery | 488,400.00 | See F | |
Cash | 488,400.00 | |||
c. | Depletion expense | 372,960.00 | See E | |
Mining Land | 372,960.00 | |||
d. | Depreciation expense | 25,200.00 | See H | |
Accumulated Depreciation | 25,200.00 | |||
When the extraction is complete then machinery would have zero value. So not necessary to use any method. |
No need to explain, please I beg just solve everything, would be greatly appreciated (thumbs up)!...
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