Question

determine the test statistic (F stat), p-value, upper critical value of F

Construct a 99​% confidence interval estimate of the difference between the two population proportions.

Let n, 50, X1 30, n2 = 50, and X2 10. Complete parts (a) and (b) below. a. At the 0.05 level of significance, is there evidence of a significant difference between the two population proportions? Determine the null and alternative hypotheses. Choose the correct answer below. В. Но: Пу S12 А. Но: п1 — П2 H1 2 H1: n12 С. Но: п12 т2 D. Ho: T1 2 H1 1 2

Answer 1

Solutions = 30 Given that , ni =50 $ 12 = 50 £ X2 = 10. P = * = -0.6 2 = 1 -= 1-0,6 3004 9= tmp q = 50(0.6)(0-4) = 3.4641 @ = x2 = 0.2 ; q= 1-7, = 0.8 şi = mpg = 1 50x0,24018 = 2.8284 ai (3.4641) F. test statistic = = = ogp (2.8284)? F-statistic = 15 upper critical value of Frantical r. 1624 = 10 762 p-value for Estert = 0.49693 i p-value Y 2 =0,05 (How i aql confidence interval is 24hin2.

= 30 - 10 + 1.762 314641)+ (2.6224)? 50 50 V = ( 18.6856 , 21.1143) i The 991. confidence interval = (18.88 , 21) The option as (A). Dull hypothesis į Ho • TTi = Tig Alternative hypothesis & Hii IT & Tz " P-value >x, So, we fail to reject the hull hypothesis. so that there 1884 evidence to a significant difference between the two population proportions. No
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