Question

0.010 moles of Sulfanic Acid waa used (1.73g)

0.010 moles of N,N dimethylaniline (1.218g)

0.68 g of Methyl Orange produced

help find likitung factor, theoretucal yield and percent yield.

Experiment #and Title: #7: Preperation of methul Orange Product Prepared: Methul Oranje Boiling Point: _Melting Point: _ _Yield in Grams: 0.689 Reaction Equation(s): ols): 1.93g of sulfenico Acid (0.010 moles) 2ome of sodium carbonate 0.69g of sodium Nitntee 1 mode of sulfonic and gives imol of methyl 1.2118g of N-N dimethylandine orange to react w Imol of dimethyl annilna, (0.01o moles) CINA 2CO3 > HO 2) UVOZ O EV=0 Ho-s 40- MO (3) 14 CI methy orange sulfanilic acid Limiting Factor: Theoretical Yield Calculations: Percent Yield Calculations:

Answer 1

Hero with a Pool Ho_l _ 27" alus Nanoa HOT sulfanilic Qeld Molecular weight 173.19 g/mol Ho-B-O MEN - H methyl orange molecular cof-327.33 g/mol Given - 1.73 g of sulfanilicacid to 0.68 methyl orange Theorotical yield - 1.73 g of sulfanilic & Imole of sulfanilic - X 173.19 g of sulfangife - acid. x ecfd Imole of methal orange Indle of sulfanilie Qefd add 327.33 g of methyl orange Imole of methyl orange = 113 imple 173 Ingle = 1.73 + 1 x 327-339 173.19 = 1-13 X 00057 327-33 g - 3.269 g

Hero with a Pool Ho_l _ 27" alus Nanoa HOT sulfanilic Qeld Molecular weight 173.19 g/mol Ho-B-O MEN - H methyl orange molecular cof-327.33 g/mol Given - 1.73 g of sulfanilicacid to 0.68 methyl orange Theorotical yield - 1.73 g of sulfanilic & Imole of sulfanilic - X 173.19 g of sulfangife - acid. x ecfd Imole of methal orange Indle of sulfanilie Qefd add 327.33 g of methyl orange Imole of methyl orange = 113 imple 173 Ingle = 1.73 + 1 x 327-339 173.19 = 1-13 X 00057 327-33 g - 3.269 g

Hero with a Pool Ho_l _ 27" alus Nanoa HOT sulfanilic Qeld Molecular weight 173.19 g/mol Ho-B-O MEN - H methyl orange molecular cof-327.33 g/mol Given - 1.73 g of sulfanilicacid to 0.68 methyl orange Theorotical yield - 1.73 g of sulfanilic & Imole of sulfanilic - X 173.19 g of sulfangife - acid. x ecfd Imole of methal orange Indle of sulfanilie Qefd add 327.33 g of methyl orange Imole of methyl orange = 113 imple 173 Ingle = 1.73 + 1 x 327-339 173.19 = 1-13 X 00057 327-33 g - 3.269 g

The ortical yfeld = 3.269 gm ④ percentage yield - perenfrege yield = Actual yield x 100 Theerofical Veld Actual yield - 0.68g .. joyfeld = 068 x 100 3.269 = 0:2080 x 100 =20.80 oro - 20.80d. percentage yield