1) An object at rest is pushed by a net force represented by the graph above....

Question

Question

Answer 1

Answer #1

change in the linear momentum of the object upto time t = area under the force-time graph of the object upto time t

As the object starts from the rest, initial linear momentum = mu = 0.

If the velocity of the object after travelling from 0 -6 seconds is v1, then,

m*(v1 - u ) = area under the force-time graph from t=0 to t=6sec

20* v1 = (0.5)* (25 +10 ) *6

20*v1 = 105

v1 = (105/20) = 5.25 sec (ans (a))

If the velocity of the object after travelling from 0 - 26 seconds is v2, then,

m*(v2 - u ) = area under the force-time graph from t=0 to t=26sec

20* v2 =( (0.5)* (25 +10 ) *6 ) +(10*(12-6)) + (0.5 * (26-12)*10)

20*v1 = (105 + 60 + 70)

v1 = (235/20) = 11.75 sec (ans (b))

Answer 2

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