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![og Electric field Intensity E z 2x I Ang CE 1 2x 57W/m² Es 3x10 m x 8.854 x 10 12 Fim 5. = 207.165] And Eq = | 2 x 10 Wim? 1](http://img.homeworklib.com/questions/a768eb40-728b-11ea-adc7-e704a4cfb949.png?x-oss-process=image/resize,w_560)
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Cellphone Radiation
Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a...
Cellphone Radiation Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a...
Cellphone Radiation
Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a cellphone has an intensity of 57 W/m2. The maximum permissible radiation leaking out from a microwave oven at the same distance is 10 W/m2. Compare the average electric fields generated by the two devices how many times stronger is the electric field that is generated by the cellphone than the maximum permissible field leaking from a microwave oven? Tries 0/12 Submit Answer A bluetooth...
Help! Please Thanks! Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from...
Help! Please Thanks!
Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a cellphone has an intensity of 29 W/m2. The maximum permissible radiation leaking out from a microwave oven at the same distance is 10 W/m2. Compare the average electric fields generated by the two devices - how many times stronger is the electric field that is generated by the cellphone than the maximum permissible field leaking from a microwave oven? 1.70 ou are correct....
Consider a cell phone that emits electromagnetic radiation with a frequency of 1.0 GHz and with...
Consider a cell phone that emits electromagnetic radiation with a frequency of 1.0 GHz and with a power of 50 W. (a) What is the electric field amplitude at a distance 1130 m away from the phone? Assume it radiates as a point source. Submit Answer Tries 0/8 (b) If your ear is only about 10 cm from the source of radiation, what is the electric field amplitude at your ear as you use the phone? Again assume the phone...
The mean distance between the Earth and the Sun is 1.50×1011 m. The average intensity of...
The mean distance between the Earth and the Sun is 1.50×1011 m. The average intensity of solar radiation incident on the upper atmosphere of the Earth is 1390 W/m2. Assuming that the Sun emits radiation uniformly in all directions, determine the total power radiated by the Sun Sulamit Answar Incorrect. Tries 1/12 Previous Tries
Please do the graph. Thanks Part 3: Effects of Distance on Radiation Intensity Radiation level Distance from source (cm) looo cm 50 com loocpM bocPm 6 2ecPm 15 CAM 9 3 PM 8 10 110 сем CS Part 3:...
Please do the graph.
Thanks
Part 3: Effects of Distance on Radiation Intensity Radiation level Distance from source (cm) looo cm 50 com loocpM bocPm 6 2ecPm 15 CAM 9 3 PM 8 10 110 сем CS
Part 3: Effects of Distance on Radiation Intensity Radiation level Distance from source (cm) looo cm 50 com loocpM bocPm 6 2ecPm 15 CAM 9 3 PM 8 10 110 сем CS
Two charges, Q1= 2.50 pC, and Q2= 6.40 pC are located at points (0,-2.00 cm )...
Two charges, Q1= 2.50 pC, and Q2= 6.40 pC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure 2, What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 0.0660 N/C The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit...
Part A II Review A hollow metal sphere has 5 cm and 9 cm inner and...
Part A II Review A hollow metal sphere has 5 cm and 9 cm inner and outer radii, respectively. The surface charge density on the inside surface is -150nC/m2. The surface charge density on the exterior surface is +150nC/m What is the strength of the electric field at point 4 cm from the center? Express your answer to three significant figures and include the appropriate units 86062 N/C Submit Previous AnswersRequest Answer X Incorrect; Try Again; 4 attempts remaining Part...
Two charges, Q1-2.30 μС, and Q2= 6.90 μC are located at points (0,-3.50 cm ) and...
Two charges, Q1-2.30 μС, and Q2= 6.90 μC are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (6.50 cm, 0), due to Q1 alone? 3.79x106 N/C You are correct. Previous Tries What is the x-component of the total electric field at P? 1.34x10 N/C You are correct. Previous Tries What is the y-component of the total electric field at P? Submit...
2 Two charges, Q1= 2.50 pC, and Q2° 6.60 μC are located at points (0,-4.00 cm...
2 Two charges, Q1= 2.50 pC, and Q2° 6.60 μC are located at points (0,-4.00 cm ) and (0, +4.00 cm), as shown in the figure. 2, What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 4.86x106 N/C You are correct. Previous Tries What is the x-component of the total electric field at P? By the principle of linear superposition, the total electric field at position P is the...
Two charges, Q1= 2.00 μC, and Q2= 6.00 pC are located at points (0,-2.00 cm )...
Two charges, Q1= 2.00 μC, and Q2= 6.00 pC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure What is the magnitude of the electric field at point P, located at (6.50 cm, 0), due to Q1 alone? The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit system Submit Answer...
Cellphone Radiation
Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a cellphone has an intensity of 57 W/m2. The maximum permissible radiation leaking out from a microwave oven at the same distance is 10 W/m2. Compare the average electric fields generated by the two devices how many times stronger is the electric field that is generated by the cellphone than the maximum permissible field leaking from a microwave oven? Tries 0/12 Submit Answer A bluetooth...
Help! Please Thanks!
Cellphone Radiation Points:3 At a distance of 5 cm, the microwave radiation from a cellphone has an intensity of 29 W/m2. The maximum permissible radiation leaking out from a microwave oven at the same distance is 10 W/m2. Compare the average electric fields generated by the two devices - how many times stronger is the electric field that is generated by the cellphone than the maximum permissible field leaking from a microwave oven? 1.70 ou are correct....
Consider a cell phone that emits electromagnetic radiation with a frequency of 1.0 GHz and with a power of 50 W. (a) What is the electric field amplitude at a distance 1130 m away from the phone? Assume it radiates as a point source. Submit Answer Tries 0/8 (b) If your ear is only about 10 cm from the source of radiation, what is the electric field amplitude at your ear as you use the phone? Again assume the phone...
The mean distance between the Earth and the Sun is 1.50×1011 m. The average intensity of solar radiation incident on the upper atmosphere of the Earth is 1390 W/m2. Assuming that the Sun emits radiation uniformly in all directions, determine the total power radiated by the Sun Sulamit Answar Incorrect. Tries 1/12 Previous Tries
Please do the graph.
Thanks
Part 3: Effects of Distance on Radiation Intensity Radiation level Distance from source (cm) looo cm 50 com loocpM bocPm 6 2ecPm 15 CAM 9 3 PM 8 10 110 сем CS
Part 3: Effects of Distance on Radiation Intensity Radiation level Distance from source (cm) looo cm 50 com loocpM bocPm 6 2ecPm 15 CAM 9 3 PM 8 10 110 сем CS
Two charges, Q1= 2.50 pC, and Q2= 6.40 pC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure 2, What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 0.0660 N/C The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit...
Part A II Review A hollow metal sphere has 5 cm and 9 cm inner and outer radii, respectively. The surface charge density on the inside surface is -150nC/m2. The surface charge density on the exterior surface is +150nC/m What is the strength of the electric field at point 4 cm from the center? Express your answer to three significant figures and include the appropriate units 86062 N/C Submit Previous AnswersRequest Answer X Incorrect; Try Again; 4 attempts remaining Part...
2 Two charges, Q1= 2.50 pC, and Q2° 6.60 μC are located at points (0,-4.00 cm ) and (0, +4.00 cm), as shown in the figure. 2, What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 4.86x106 N/C You are correct. Previous Tries What is the x-component of the total electric field at P? By the principle of linear superposition, the total electric field at position P is the...
Two charges, Q1= 2.00 μC, and Q2= 6.00 pC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure What is the magnitude of the electric field at point P, located at (6.50 cm, 0), due to Q1 alone? The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit system Submit Answer...
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