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Two charges, Q1= 2.50 pC, and Q2= 6.40 pC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure 2,What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 0.0660 N/C The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulombs Law. Remember to convert all units to the SI unit system. Submit Answer Incorrect. Tries 1/12 Previous Tries What is the x-component of the total electric field at P? 0.581 NiC By the principle of linear superposition, the total electric field at position P is the vector sum of the electric field cóntribution from charge Q1 and Q2. Submit Answer Incorrect. Tries 1/12 Previous Tries What is the y-component of the total electric field at P? Submit Answer Tries 0/12 What is the magnitude of the total electric field at P? Submit Answer Tries 0/12 Now let Q2 = Q1 = 2.50 μC. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P? 0.124 N Can you say anything about the y-component of the total electric field before you start calculating? Submit Answer Incorrect. Tries 1/12 Previous Tries Fiven the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point Submit Answer Tries 0/12

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