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Two charges, Q13.30 HC, and Q2 5.10 HC are located at points (0,-2.50 cm) and (0,+2.50 cm), as shown in the figure What is the magnitude of the electric field at point P, located at (5.00 cm due to Q1 afone? 9.49x106 N/C You are correct. Previous Tries What is the x-component of the total electric field at P? 2.58 10 6 N/C By the principle of linear superposition, the total electric field at position P is the vector sum of the electric field contribution from charge Q1 and Q2. Previ Tries Submit Answer You have entered that answer Incorrect. Tries 2/12 before What is the y-component of the total electric field at P? -2.32x106 N/c You are correct. Previous Tries What is the magnitude of the total electric field at P? 3.469 10*6 N/C The electric field at point P is a vector quantity. Review vector addition and recall that Ep =sqrt( EpXR2 + Ерућ2 ) Submit Answer Incorrect. Tries 1/12 Previous Tries Now let Q2 Q13.30 HC. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P? 3.469 10*6 N/C Can you say anything about the y-component of the total electric field before you start calculating?

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Answer #1

Sg 5 31 3x10kg.yx5시0x10 (5.s1) 6 = 2x gx13x 3.30x10x s-ほ.ot, 2x16 Nlc S X10 E, sin θ EN Es equs

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