Question

2 Two charges, Q1= 2.50 pC, and Q2° 6.60 μC are located at points (0,-4.00 cm ) and (0, +4.00 cm), as shown in the figure. 2, What is the magnitude of the electric field at point P, located at (5.50 cm, 0), due to Q1 alone? 4.86x106 N/C You are correct. Previous Tries What is the x-component of the total electric field at P? By the principle of linear superposition, the total electric field at position P is the vector sum of the electric field contribution from charge Q1 and Q2. İncorrect. Tries 3/12 PreviousTies Submit Answer What is the y-component of the total electric field at P? Subnit Anawer Tries 0/12 What is the magnitude of the total electric field at P? Submit Answer Tries 0/12 Now let Q2 = Q1 = 2.50 μC. Note that the problem now has a symmetry that you should exploit in your solution, what is the magnitude of the total electric field at P? Submit Aneswer Tries 0/12 Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P? Submit Anewer Tries 0/12

Answer 1