Question

1. Consider a 0.575 M solution ascorbic acid (H2CH&O) also known as Vitimin C (pKa= 4.10 and where pKa2 11.80.) a. First write out the two acid dissociation equilibrium reactions that occur in this solution (4pts) b. What is the pH, [HC HO ] and [C H&O 1 (8pts) 2. What is the approximate pH of a solution of 0.620M NaCaH&O? Here you can refer to the equilibrium constants in question 2, assume this compound is fully soluble, (4pts)

Answer 1

- a) 1 (12) H₂ GHEO AGACO HGHOG 4t È CHag² + 4t , ka, , ka 6.) H₂6466 Nanoo tut H₂CG HOOG 0575m 2 y535-X (we can regleux) ka, a 2 10 4.10 7.9x105 CuHo Cut) (264%). 3-9x16% x2 + 7.9x10TX - 4.5425x10 20 use quadratic equation solver, I get x 2 8-0067 m. 2 CHA) 20-0067m. Ma log Co-0067 m) 2 (2017) CH) from second lani zaton negngible as difference I between phos and phas lave JCHG4606) 2 CHT) 2 10-0067m) second ronization F не се е сен Oro 67m 0.0067m o 0.0067 - 2 00067 neglect x as ka is very less Kaja (640XHt) kar 2 10 101180) (HGH ) 2 1.6x 10th

1-6*10-12 ₃ C M g 2 Co-1867) Co-cost] Con62) 21-6x1072 m e) is & NOHGH cor) wa 646% (confirm) L or if it is NGHGH6% then HGH605 15 ampeloseve Cacts as p ph a plat tpilar 2 4 .10+11.80 acld & base 27-95- - It 2 r as Hoga Cre Na64%), it acts as base, then uplar + pkb) a 14.00 2) Picbl, 14.00 - 11:30 2) Ko, 2 100kb, - C6H662 t mo ² NGH5 ton 60-620- calcolote on using quadranc ecuation then carcerate on then pH. solver,