a) The dissociations that occur are:
H2C6H6O6 = H + + HC6H6O6-
HC6H6O6- = H + + C6H6O6-2
b) Ka is calculated:
Ka1 = 10 ^ -pKa1 = 10 ^ -4.1 = 7.9x10 ^ -5
Ka2 = 10 ^ -11.8 = 1.6x10 ^ -12
You have the expression of Ka1:
Ka1 = [HC6H6O6-] * [H +] / [H2C6H6O6]
7.9x10 ^ -5 = X ^ 2 / 0.575
It clears X = 0.007 M
PH is calculated:
pH = - log 0.007 = 2.15
You have the second dissociation:
Ka2 = [C6H6O6-2] * [H +] / [HC6H6O6-]
1.6x10 ^ -12 = [C6H6O6-2] * 0.007 / 0.007
It clears [C6H6O6-2] = 1.6x10 ^ -12 M
2) Kb2 is calculated:
Kb2 = Kw / Ka2 = 10 ^ -14 / 1.6x10 ^ -12 = 6.25x10 ^ -3
The expression of Kb2 has:
6.25x10 ^ -3 = X ^ 2 / 0.62
It clears X = 0.062 M
POH and pH are calculated:
pOH = - log 0.062 = 1.21
pH = 14 - 1.21 = 12.79
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