QUESTION 1 A DVD is spinning at 511.38 rpm. What is the size of the angular...

Question

Question

QUESTION 1 A DVD is spinning at 511.38 rpm. What is the size of the angular momentum of the DVD if it has a circumference of

Answer 1

Answer #1

given

w = 511.38 rpm

= 511.38*2*/60 rad/s

= 53.551 rad/s

2*pi*r = 33.912 cm

r = 33.912/(2*pi)

= 5.39726 cm

= 0.0539726 m

m = 10.673 g

= 0.010673 kg

angular momentum, l = I*w

= (1/2)*m*r^2*w

= (1/2)*0.010673*0.0539726^2*53.551

= 8.3247*10^-4 kg.m^2/s <<<<<<<<<<-------------------Answer

Answer 2

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