Angular velocity of the DVD,
= 592.309 rpm
Convert the unit of angular velocity in rad/s -
= (592.309 / 60)*(2*pi) rad/s = 62.01 rad/s.
Now, circumference of the DVD = 39.543 cm
Hence, its diameter, d = (39.543) / (pi) = (39.543) / 3.141 = 12.59 cm
Hence, its radius, r = d/2 = 12.59/2 = 6.29 cm = 0.0629 m
Mass of DVD, m = 10.803 g = 0.010803 kg
So, moment of inertia of DVD about its center point, I = (1/2)*m*r^2
= (1/2)*0.010803*0.0629^2 = 2.14 x 10^-5 kg*m^2
Therefore, angular momentum of the DVD, L = I*
= 2.14 x 10^-5 kg*m^2 x 62.01 rad/s
= 1.327 x 10^-3 kg*m^2/s
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