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[H30+] and [OH-] In Solutions OH 4x 10-12 M (OH 3x 10 M L но 8 x 10-10 M (OH 7 x 10-13 M OH [- но! 4 x 10-2 M 8 x 10 M он 1 6
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Answer #1

we know that, pH = -log [tt] polt = -log [OH- pH + polt=14 on, pH = 14-pot (1) [OH-] = 4x100m (2) [OH-] = 3x109m pold = -logpH = 14-1:39 3 [OH-] = 4x10²m 16) [OH-] = 8x107m. pOH = -log (4x102) pot = -log (8810) = 1.39 = 3.09 pH = 14-3.09 = 12.61 (Ba

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