4. A 202. gram sample of copper (C =0.20 j/g-deg. C) is heated to 85.0 deg....

Question

Question

Answer 1

Answer #1

Let final temperature is T oC

heat released by copper = heat gain by water

or

m1 * C * dT1 = m2 * s2 * dT2

or

202. * 0.20 * (85.0 - T) = 100.0 * 4.184 * (T - 19.2)

or

(85.0 - T) = 10.36 * (T - 19.2)

or

283.8 = 11.36 T

or

T = 24.995 = 25.0 oC

thus

final temperature is 25.0 oC.

Answer 2

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