4. A 47.4 g sample of a metal is heated to 95.2°C and then placed in...
A 45.90 g sample of pure copper is heated in a test tube to 99.40°C. The copper sample is then transferred to a calorimeter containing 61.04 g of deionized water. The water temperature in the calorimeter rises from 24.47°C to 29.10°C. The specific heat capacity of copper metal and water are J J 0.387 and 4.184 respectively. gr°C g. °C Assuming that heat was transferred from the copper to the water and the calorimeter, determine the heat capacity of the...
A 45.90 g sample of pure copper is heated in a test tube to 99.40°C. The copper sample is then transferred to a calorimeter containing 61.04 g of deionized water. The water temperature in the calorimeter rises from 24.39°C to 29.10°C. The specific heat capacity of copper metal and water are J J 0.387 and 4.184 respectively. - 9 Assuming that heat was transferred from the copper to the water and the calorimeter, determine the heat capacity of the calorimeter....
A 21.3 g sample of a metal was heated to 61.67°C. When the metal was placed into 17.8 g of water in a calorimeter, the temperature of the water increased from 25.00°C to 30.00°C. What is the specific heat of th metal? The specific heat of water is 4.18 J/g. °C). Specific heat- J/g °C) Submit Answer Try Another Version 10 item attempts remaining
2. (15 pts) A 83.5 g sample of a metal alloy is heated to 88.1°C and it is then placed in a coffee-cup calorimeter containing 30.0 g water at 15.0°C. The final temperature of the metal + water is 25.3 °C. Calculate the specific heat of metal alloy, in J/(g°C), assuming no heat escapes to the surroundings or is transferred to the calorimeter. The specific heat of water is 4.184 J/(g°C).
QUESTION 5 2 points Check all the compounds below that are products in the follow reaction. Na2SO4 (aq) + Cu(NO3)2 (aq) Cu2SO4(s) NaNO3(aq) CuSO4(s) no reaction NaNO3(s) H20 QUESTION 6 4 points A 44.98 g sample of a metal is heated to 95.2°C and placed in a calorimeter containing 181.0g of water (c = 4.184 J/g °C) at 22.2°C. The final temperature of the water is 24.1°C. Neglecting any heat lost to the calorimeter, which of the following metals was...
A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 73.8 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Please be super specific on how you get to each step!
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...
A 45.90 g sample of pure copper is heated in a test tube to 99.40°C. The copper sample is then transferred to a calorimeter containing 61.04 g of deionized water. The water temperature in the calorimeter rises from 24.47°C to 29.10°C. The specific heat capacity of copper metal and water are J J 0.387 and 4.184 respectively. g•°C g.°C' Assuming that heat was transferred from the copper to the water and the calorimeter, determine the heat capacity of the calorimeter....
A 83.5 g sample of a metal alloy is heated to 88.1oC and it is then placed in a coffee-cup calorimeter containing 30.0 g water at 15.0oC. The final temperature of the metal + water is 25.3 oC. Calculate the specific heat of metal alloy, in J/(g oC), assuming no heat escapes to the surroundings or is transferred to the calorimeter. The specific heat of water is 4.184 J/(g oC).
A 94.1 g metal sample is heated to 102.4°C and transferred to 100.0 g H20 at 22.0°C in a calorimeter. Equilibrium temperature is 26.4°C. Specific heat of metal is? {SH20=4.184 J/gºC; q=smAT; AT=Tfinal-Tinitial} Answer to 2 significant figures. Do not include the unit 18°C