Question

A 10cm×10cm square is bent at a 90∘ angle. A uniform 7.00×10−2 T magnetic field points downward at a 45∘ angle.(Figure 1)
5 em 10 cm 45f 5 cm

What is the magnetic flux through the loop?

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Answer #1

Given, B= 7x10-2T. 0=45° : Magnetic fux through the loop (Ø):- 0 = BACOSO = (7x10-)(0:1)2(CO3 45°). 1.0. = 4094x10-4 weber. [

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