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We know that system.out.println (“object number” + n ); is legal.String name; int n; name =...

We know that system.out.println (“object number” + n ); is legal.String name; int n; name = “object number” + n; See if you will get a compiler error. Is there a way to get around the error?

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Answer #1

First of all system.out.println (“object number” + n ); is a print statement and treats every argument inside it as a separate argument. Its not concatenating! Its simply throwing its arguments (be it string, integer etc..) to the output stream. Second, String name; int n; name = “object number” + n; is fairly legal, if the variable 'n' is initialized to a value. There is no reason you should get an error.

Also, as another method, java has string methods to convert numeric values to string:

  • String.valueOf(number)
  • Integer.toString(number)
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