Question

XIncorrect; Try Again; 4 attempts remaining Part C How many grams of CO2 are produced from the complete reaction of 51.4g of C4H10? Express your answer with the appropriate units. ? Value m(CO2) Units Request Answer Submit Part D If the reaction in part e produces 145 g of CO2, what is the percent yield of CO2 for the reaction? Express your answer with the appropriate units. The percent yield ofCO3 Value Units Submit Request Answer Provide Feedback MacBoolk esc

Answer 1

2C4H10(g) + 13O2(g) ----------------------> 8CO2(g) + 10H2O(g)

2 moles of C4H10 combustion to gives 8 moles of CO2

2*58g of C4H10 combustion to gives 8 *44g of CO2

51.4g of C4H10 combustion to gives = 8*44*51.4/(2*58)   = 156g of CO2

theoretical yield of CO2 = 156g

actual yield of CO2   = 145g

percent yield   = actual yield*100/theoretical yield

                         = 145*100/156   = 92.95%    >>>>answer