Question

7. Consider the following piston-cylinder arrangement which is thermally insulated. Initially, the same 1 mole of ideal gas are confined in the cylinder A, B and C, respectively which are partitioned by a adiabatic piston and a diathermic piston as shown in Figure 1. The initial volume and absolute temperature (K) of three partitions are the same as Vand T, respectively and the pressure of the cylinder is given by P, as shown in Figure 1. When heat (q) was gradually supplied to A, the gas of A was reversibly expanded until the volume of C cylinder is and it was then reached at the final equilibrium as shown in Figure 2. (Suppose that the molar heat capacity is C = 2R In addition, assume that the friction between the cylinder and the piston and the mass of the piston are ignored. The heat capacity of a diathermic piston is also ignored.) Thermally insulated Adiabatic piston cylinder Adiabatic piston P. V.T + B В -v C Figure 2 Figure 1 Diathermic piston P.V. Calculate the value of .
plz

Answer 1

cim=aR Com=3R A t 500/2 v =3 pat volu same an alle equilibrium is when pressure is let P. volume of A = Svor volume of B = Volu volume of cavol c=volu New pressure of B and C finally Po (2vo) = p. ♡ | vor I at any time P. (20-v1] Psevd - Papo 2² = 8Po => P = Povor PA finally should be PA = 8 Po : Povo = 8po. 500/2 To =) T =20 To pst law of Thermodynamics, q = 1x 2Rx (19 To) + Povo here : (voru) v is the volume in Bo 9= 38 Polot Poror x Sco- use av

9=38 Povot Pol -Y+! 9= 38 P. Vo + Povou a favor 90 36 teve = exoma f* *_(2014 q= 38 Po Vot Poro" (CTS –vo") 9= 38 Povo + Povo -3 +1 ) 9= 38 POVO + Po Vo "=(-2) ( 2 9 = 38 Povo - zpovo q= 36 Povo » Polo = Answer.