molarity of H2 = no of moles/volume in L
= 0.293/1 = 0.293M
molarity of I2 = no of moles/volume in L
= 0.293/1 = 0.293M
------H2(g) + I2(g) ---------------> 2HI(g)
I ---- 0.293 ------ 0.293 ---------------- 0
C---- -x -------- -x -------------------- 2x
E --- 0.293-x---- 0.293-x ------------ 2x
Kc = [HI]^2/[H2][I2]
55.6 = (2x)^2/(0.293-x)(0.293-x)
55.6 = (2x/(0.293-x)^2
7.45 = 2x/0.293-x
7.45*(0.293-x) = 2x
x = 0.23
[H2] = 0.293-x = 0.293-0.23 = 0.063M
[I2] = 0.293-x = 0.293-0.23 = 0.063M
[HI] = 2x = 2*0.23 = 0.46M
The equilibrium constant, K, for the following reaction is 55.6 at 698 K: H2(g) + 12()...
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