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4cK + N2+ 4H20—>N,H4 + 2Cl2+ 40H In the above reaction, the oxidation state of nitrogen changes from to - How many electrons
Cd + C10+ 2H+ --Cd2+ + C103+H20 In the above reaction, the oxidation state of cadmium changes from - to - How many electrons
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Answer #1

400 & ₂ & 4H20 - Na Hy & 202 + 4015 (-2) N2 N₂ Hy 2x 2x = 0 + 4 (1) = 0 2x = -4 oxidation state of Nitrogen changes from (0)ca - clou + 2H+ Cd²+ & cloš + to oxidation state of cd changes (o) to (+2) é transforred = 1x (2-0) = 2 .

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