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A 3-ethylcyclohexan-1-one reacts with both propMgBr, and water. In the first part of the reaction, the...

A 3-ethylcyclohexan-1-one reacts with both propMgBr, and water. In the first part of the reaction, the propane part of propMgBr takes the bonding electrions from MgBr, becoming a carbanion. The carbanion attacks the slightly positive carbon of the carbonyl group. The pi obnd between the oxygen and carbon break, and the electron pair moves toward the oxygen atom. Now the intermediate reacts with water. First a hydrogen atom loses it's bonding pair to the oxygen in the water molecule. Now the negative alkoxide attacks the proton, and a hydroxide ion as a byproduct, and 2-ethyl-1-propylcyclohexan-1-ol. Can someone help me sketch this mechanism with arrows showing what is being moved
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--- - 2 Hit-ct, — сH— Tj — В1 рrор нува 3-etylcyclohexanone (ketone) (Intermediate) те) How (Јако (products Bekyl- l-propyl C

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