Question

A student measures the potential of a cell m in the other. There is a copper electrode in the CuSO, and a silver electro student finds the potential of the cell, Ecall to be 0. e potential of a cell made up with 1 M Cuso, in one solution and 1 M AgNO, the Cuso, and a silver electrode in the AgNO,. The otential of the cell, E., to be 0.47 V, and that the copper electrode is negative. 1. At which electrode is oxidation occurring? 2. Write the half-reaction taking place at the anode: 3. Write the half-reaction taking place at the cathode: . given that the potential of the silver, silver ion electrode, E ., is taken to 4. What is E be 0.00 V?

Answer 1

anode reaction. oxidation is occuring at anode. Culcusoy electrode. iction : Ca(s) - Cu2+ (aq.) + 2€ Cathole reaction: Age cap) té - Ag(s) E cel = -E anode + E' cathode Eagh ag=0.00 V (considered) 0.47V - - Fanode + 0.00u = Fanocie = -0.47V (Arower) 0.47= 0.80 - Eanude Eme= 0.801-0.47= 0.33V (Answer) Net cell equation (ionic): anode san + ax cathode oxn. Cu(s) + 2 Ag@lap.) → Cuz*raq) + 2Ag (1) Fe = 0.96V> Excu- crocal, log Cart = 0.47-0-05PI log Carey Caza) = 2.6178x16" M = 2.6X1612 m camwer) K= [ling Palm2°, .6415"ºx(3)* = 212X16'3 (Answey ® TCG (NH22 0.01 0