Question

Please help with 1-8

A student measures the potential of a cell made up with 1 M CuSO, in one solution and 1 MAgNO, in the other. There is a copper electrode in the Cuso, and a silver electrode in the AgNO, The student finds the potential of the cell, Eo be 0.45 V, and that the copper electrode is negative. 1. At which electrode is oxidation occurring? 2. Write the half-reaction taking place at the anode: 3. Write the half-reaction taking place at the cathode: 4. What isgiven that the potential of the silver, silver ion electrode, E r, A, is taken to anode be 0.00 V?

Answer 1

1) oxidation occurs at copper electrode

2) Half reaction at anode

Cu_(s) $\rightarrow$ Cu ²⁺_{( aq)} + 2 e^-

3) Half reaction at cathode

2Ag+ _(aq) + 2e^- $\rightarrow$ 2 Ag_(s)

4) E ⁰_Cell= E⁰_cathode - E⁰_anode  

Here E⁰ _cathode= 0.0 V then   -E ⁰_Cell = E⁰_anode =- 0.45 V

5) E⁰_anode = E⁰ _cathode -  E ⁰_Cell

= 0.80 - 0.45

= 0.35 V

6) net reaction in cell

Cu_(s) + 2Ag+ _(aq) $\rightarrow$ Cu ²⁺_{( aq)} +  2 Ag_(s)