Question

Q4) (20 Mark) Monitor three consecutive packets going through an Internet router. Classify each one as either video (v) or data (d). Your observation is a sequence of three letters (each one is either v or d). For example, three video packets correspond to vvv. The outcomes vvv and ddd each have probability 0.2 whereas each of the other outcomes vvd, vdv,vdd, dvv, dvd, and ddv has probability 0.1. Count the number of video packets NNVV in the three packets you have observed. Describe in words and also calculate the following probabilities: (a) PlNv= 2] (b) PINv 21] (d) Pl(ddv Nv 2

Answer 1

7 No No. of video packers out of 3 packet, Given that p(um) = n(dad) = 0.2. . Pudicrud) panda). (dub)pd.) Plddee) : 0.1. a> P(No=2) - P(10d10) + P(1920). + P(441010) 0.14 0.1 +0.1 = 0.3 (Avs), b). Penox,1) = P(No 21) TP(No =2) + P(No=3) a> p [ord I No E P[ood n Ne=2 - PENU=2]. D1 Arp Pred] PENU=27 .. a> p [dda N=2] Pcddun Ne=2] PONU: 2] peatu]. 2011 PCN=2] - Yg (Ams)

PC Nive=2 >, 11 PONqs = 20 Nat),13 PENs > ] . PeNq=2). PENY, I] . 3/(). P [ Nes, I Nas = 2 ] . PCN79, 1 n Nes=2]. PC Nas=2]. PENU=2]. PCNDS = 2] : - 1 (Avs).