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Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermomete

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean

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Answer #1

solution:

= P( 1.50< Z <2.25 )

= P(Z <2.25 ) - P(Z <1.50 )

Using z table,  

= 0.9878-0.9332

=0.0546

-3 -2 - ó i

b.

= P( -2.12< Z <3.73 )

= P(Z <3.73) - P(Z <-2.12 )

Using z table,  

= 0.9999-0.0170

=0.9829

3 2 1 0 1 2

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