Solution
Using standard normal table
a) P (0.75 < Z < 1.75)
P ( Z < 1.75 ) - P ( Z < 0.75 )
= 0.9599 - 0.7734
= 0.1866
Probability = 0.1866
Option c ) is correct
b ) P ( Z < z ) = 89%
P ( Z < z ) = 0.89
z = 1.23
Option b ) graph is Percentile P89
Assume that thermometer readings are normally distributed with a mean of O'C and a standard deviation...
Assume that thermometer readings are normally distributed with a mean of O'C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested For the case below, draw a sketch, and find the probability of the reading (The given values are in Celsius kres.) Between 0.75 and 1.50 Click to view page 1 of the table. Click to view page 2 of the table Draiv a sketch. Choose the correct graph belon ОА. -0.75 -1.50
Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. ОА. OB. OC. 0 0 5...
Assume that thermometer readings are normally distributed with a mean of o°C and a standard deviation of 1.00°c. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.25 and 1.25 Click to view page 1 of the table, Click to view page 2 of the table Draw a sketch. Choose the correct graph below A. Ов. Ос. z 0.25 1.25...
Assume the readings on thermometers are normally distributed with a mean of OC and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads greater than 0.24 and draw a sketch of the region. Click to view of the table. Click to view page 2 of the table ОА The probability is
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested Draw a sketch and find the temperature reading corresponding to the 88th percentile. This is the temperature reading separating the bottom 88% from the top 12%.Which graph represents Psa? Choose the correct graph below The temperature for Pas is approximately _______ (Round to two decimal places as needed)
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of O'C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than -0.972°C. P(Z > - 0.972) = Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and...
assume that the readings on the thermometers are normally distributed with a mean of 0 and standard deviation of 1.00 C. A thermometer is randomly selected and tested. dran a sketch and find the temperature reading corresponding to P 83 the 83rd percentile. this is yhe temperature reading separating the bottom 83% from the top 17%.
Assume that thermometer readings are normally distributed with a mean of 0 degrees °C and a standard deviation of 1.00 degrees °C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.25 and 1.75
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads between - 1.62 and - 0.91 and draw a sketch of the region. Click to view page 1 of the table. Click to view page 2 of the table. Sketch the region. Choose the correct graph below. O A. OB. Oc. The probability is Click to select your answer(s). Find the indicated...
Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees. 0° and standard deviation of 1.00 °C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P 91. P91, the 91 st percentile. This is the temperature reading separating the bottom 91 % from the top 9 %. A. graph representing the Upper P 91 B. The temperature for Upper P 91 P91 is approximately...