1)
Given:
lambda = 0.250 km = 2.5*10^2 m
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(2.5*10^2 m)
= 7.951*10^-28 J
Answer: 7.95*10^-28 J
2)
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 7.951*10^-28*6.022*10^23 J/mol
= 4.788*10^-4 J/mol
Answer: 4.79*10^-4 J/mol
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