Question

NaOH solution Add Base 1.00 ml 0.10 mL Base Added 10.10 ml 0.05 mL Experimental Settings Indicator Methyl orange [NaOH] = 0.5
1 of 1 The flask contains 25 mL of an unknown diprotic acid aqueous solution that reacts in a 1:2 stochiometric ratio with Na
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Answer #1

concentration of the unknown acid solution = 0.101 M

Explanation

Concentration NaOH = 0.50 M

volume NaOH added = 10.10 mL

moles NaOH added = (Concentration NaOH) * (volume NaOH added)

moles NaOH added = (0.50 M) * (10.10 mL)

moles NaOH added = 5.05 mmol

moles acid = (moles NaOH added) / 2

moles acid = (5.05 mmol) / 2

moles acid = 2.525 mmol

concentration of acid = (moles acid) / (volume of acid)

concentration of acid = (2.525 mmol) / (25 mL)

concentration of acid = 0.101 M

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