Question

can I get the work as well please? thanks

While walking, you often make horizontal turns. Imagine making a right horizontal turn along a circular path, with diameter of 0.25 m. If you are walking 3.8, without slipping, determine the net external force you must experience to negotiate the turn. (Assume your mass is 98 kg.) MOSS-98 situs i. 1490 N 0.251 0.25m-dia (ii. 2980 N iii. 5660 N iv. 11300 N v. There is not enough information to solve this problem. Moss -98kg

Answer 1

3 The centrifugal force on the person is mv2 which is acting away from the center , & the friction on the person is towards the center a this frictional force balances the centrifugal force ginen, ma 98kg. the radius of the circular path =) p = 0.125 m f The is v= 3.8 mis net fonce with respect the frictional force. to ground

force on the hence, person the net is = mul > 98(3.8) N 0.125 So, = 11320.96 N in the nearest appoonimation connect option is iv) 11300N the @ Now, the frictional force on the person is towards the center, & this force balances the centrifugal fonce. So, by newton's 3nd law the force on the flood is opposite to that of force on you. ie, away from the center. rence, i The the turon floor, in the center centrifugal force during is the friction on the the direction away from of the circle.