Consider the following application of Bernoulli's equation: 0.5ρv21+(P1−P2) = 0.5ρv22. Assume that P1<P2, and both speeds (v1 and v2) are greater than zero.
Select the qualitative Bernoulli bar chart that is consistent with the equation.
Since
Therefore by above equation
Therefore
Or
Or
Therefore
Thus
bar will be low and
or kinetic energy
bar will be high
And
bar will be high and
or kinetic energy
bar will be low
These conditions are satisfied by 4th option. Therefore 4th option is correct
Consider the following application of Bernoulli's equation: 0.5ρv21+(P1−P2) = 0.5ρv22. Assume that P1<P2, and both speeds...
Problem 2 EXAMPLE OF BERNOULLI'S EQUATION P-150,000 Pa v1 = 5.0 m/s h1=0.0m Al x1 P2 1000 kg/m3 V2- 10 m/s h2h2= 2.0 m g= 9.8 m/s 2 2
K, tugi +(li-P)= K2 + Ug2 0 Part B A situation that can be represented by by the qualitative Bernoulli bar chart shown in the figure (Figure 1) is as follows: The flow speed of water in a constricted section of a pipe having cross-sectional area A1 is v1. In the regular section of the pipe, the cross-sectional area is A2 and the flow speed is v2. Determine the pressure in a constricted section of a pipe if the pressure...
Using Bernoulli's equation, the calculated pressure P0 is:
a.) 321213 dyne/cm3
b.) 135263 dyne/cm3
c.) 452647 dyne/cm3
d.) 128513 dyne/cm3
P.. = Pressure Atmospheric time= 7s h1 = 13cm hcl = 6.3 cm Diameter = 11.5cm Reservoir B height = 21 cm h.2 = 13.2 cm h.cpl = y cm h; = 13 lcm P1 = Pressure column h.cp2 = xcm Velocity(v.) Pipe Diameter = 3.6cm P2 = Pressure column Area.p1 Velocity (V2) Тар А hpl = 73.2 cm Pipe...
P1=
5 bars, P2 = ?, V1 = .3 m^3 , V2 = .7 m^3, Cv = .5 KJ/kgK, dv = 2.5
KJ/kg
*du
= 2.5 KJ/ Kg
PART B(1) A gas mixture expands with a known pressure-volume relation, PVConst. The gas mixture behaves as an ideal gas. The process is polytropic with n=1.3. Kinetic and Potential energy effects are or (plv1)in(v2/v1), dU=mCvdT, 1 bar-10 N/sq.m, 1 kJ-10 N.m, Universal gas constant(R)- 8.314 kJ/(kmol.K)= MR, Please refer to the given...
Consider the hypothesis test below. H. : P1 - P20 H. : P1 P2 > 0 The following results are for independent samples taken from the two populations. Sample 2 Sample 1 11 = 100 ©1 = 0.27 n2 = 300 P2 = 0.18 Use pooled estimator of p. a. What is the value of the test statistic (to 2 decimals)? .16 b. What is the p-value (to 4 decimals)? 1.89 c. With a = .05, what is your hypothesis...
Darth Maul is getting rather advanced at Bernoulli's equations, so he decides to tackle a slightly more complicated situation. Suppose the gauge pressure on the top surface of the fluid in the vessel is given by P2. (Remember, gauge pressure is just how much higher the pressure is relative to the the pressure outside the vessel (i.e. 1 atm, in this case.) Darth Maul needs help determining a formula (in letters) for the speed, v1, at which liquid flows from...
Binary mixture at vapor-liquid equilibrium at constant temperature has total pressure P=1.57 bar at x1=0.3. The vapor pressures of pure components are P1=2.06 bar and P2=1.13 bar, respectively. Assume that the vapor phase is ideal and the liquid phase non-ideality can be described by 1-parameter Margules equation . Calculate the total pressure and the vapor composition for this mixture at x1=0.6 at the same temperature
You wish to test the following claim (H1H1) at a significance level of α=0.02α=0.02. Ho:p1=p2Ho:p1=p2 H1:p1<p2H1:p1<p2 You obtain 33.7% successes in a sample of size n1=718n1=718 from the first population. You obtain 42.5% successes in a sample of size n2=414n2=414 from the second population. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value...
Consider the Producer-Consumer problem Assume that there are 2 producers (P1 and P2) and 1 consumer (C1). The maximum number of items in the queue is 100. Consider the following solution The functions qfull enque and deque are the standard functions discussed in class Assume they have been implemented correctly by one of the methods Semaphore ni=0, mutex=1; /* ni= number of items currently in the queue.*/ /* mutex is used to provide critical section. */ Code of a Producer...
2 moles of compressed air (diatomic gas) in a cylinder under the initial condition T1=573K p1=500kPa. Found v1=0.019m^3 but can not remember then how to find V2. I think that it has something to do with T1=T2 condition then P2 can be found.... but stuck on how to proceed so with FULL written explanations with working would be much appreciated! All question info on practice exam below - note ISOTHERMAL EXPANSION. for part ii which after an explanation first. Two...