Question

sods pts each) Patsy placed 2.6089 g of an unknown malachite mixture into a ble. The following are the data collected in the lab: mit de Mass of crucible + mixture before heating: 25.4824 g Mass of crucible + mixture after heating: 25.2444 g Calculate the following ***BOX YOUR FINAL ANSWERS***): i. Mass of H2O + CO2 lost: low or Jam e nto total -botines 150619 25.48249 - 25.24449= 0.24059) OSM slo ateien ii. Moles of H2O + CO2 lost (molar mass of H20 = 18.01 g/mol; CO2 = 44.01 g/mol): 2405 iii. Moles of malachite in mixture: Santo Tolosi H2o, coif I mole maluchle I mole Hee, col 221.11 g/mol Tlmol 120, con lo 63.039 Imd malucht = 10.84369

Answer 1

MO Mass of tot Mass of malachito mixture before a ll heating - 2.6089 Mass of glass mass of malachite - 25.48 2. e4824 g Crucible mixture before lol heating on " Mass of glass Crucible at 2.6089 = 25.4824 g => Mass of glass Concible = 25.4824-2, 6089 il = 22.87351 g Mass of misture after I 25.2444 g caneible mass of t => 22.8735+ mixture after = {25.2 444 gra28958) i llon-sult heating 203270429 i mass of mixture - (252444 -22.8735) g after heating a 2.3709 g ! Since H₂O + com is lost during heating in Mass of H₂O + Co. = 2.6089 -213709 = 0.2389 heating online in molar mass of H2O = 18:01 g/mol Tor 11 11 11 co₂ = 44.01 g/mol | 3 | 4 | H, O + 0, (18:+ 44:01) |-- = 62.02 gimo This implies 1 mole of H2O + CO₂ = 62.02 go " 0.238 g of H₂O + CO₂= I x 01238 g 62.02 g morti = 0.0038 moles

ciu) Mass of mixture - 2.3709 g. after heating - rolar mass of malachite - 221.12 g/mol This simples 221.12g of molachite = 1 mot => lg u . I mot 221.12 1X2+37099 2.3709 g of malachite - - 221.12 ginde - 0.0107 moles