1. The T distribution can be use when comparing two population with population variance unknown. True...
1. The T distribution can be use when comparing two population with population variance unknown.
True
False
2. You may use the Normal distribution when comparing two population with population variance known.
True
False
Homework Answers
1)
TRUE
The T distribution can be use when comparing two population with population variance unknown. The degree of freedom is n1 + n2 -2.
In such case we used sample standard deviations S1 and S2 respectively.
2)
TRUE
The Normal distribution may used when comparing two population with population variance known.
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1. The T distribution can be use when comparing two population
with population variance unknown.
True...
True or false? When the population variances are known, the test statistic that we use to...
True or false? When the population variances are known, the test statistic that we use to compare two population means using two independent samples follows the standard normal distribution. True or false? A paired t-test with two columns of 8 observations in each column should use d.f =7
A normal distribution is approximated as a Student t distribution when the population standard deviation is...
A normal distribution is approximated as a Student t distribution when the population standard deviation is unknown. Select one: True on O False
1. Select all true statements about sample mean and sample median. A) When the population distribution...
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comparing the means of twoindependent population when the population variances are known andunknown1....
Comparing the means of two
independent population when the population variances are known and
unknownSuppose you conduct a study and intend to use a hypothesis test to compare the means of two independent populations. Your null hypothesis is that the two means are equal. That is, \(\mathrm{H}_{0}: \mu_{1}=\mu_{2}\), or equivalently, \(\mathrm{H}_{0}: \mu_{1}-\mu_{2}=0\). Following is a table of the information you gather. Assume the populations from which your samples are drawn are both normally distributed.Sample SizeSample MeanSample VarianceSample 1n_(1)=41bar(x)_(1)=14.3s_(1)^(2)=67.24Sample 2n_(2)=21bar(x)_(2)=13.6s_(2)^(2)=46.24
When using the t distribution to calculate a confidence interval
When using the t distribution to calculate a confidence interval (because the population standard deviation is not known), we assume that the population of interest is normal or approximately normal.TrueFalse
10. A normal population with an unknown variance has a mean of 20. Is one likely...
10. A normal population with an unknown variance has a mean of 20. Is one likely to obtain a random sample of size 9 from this population with a mean of 24 and a standard deviation of 4.1? If not what conclusion would you draw. Here are some integrals you may find helpful, where h(t) is the probability distribution function for a t-distribution with 8 degrees of freedom h(t)dt = ht) dt = h(t) dt 0.919 0.653 0.983
Question 1 Tests comparing 2 population means can be: surveys experiments both surveys and experiments Question...
Question 1 Tests comparing 2 population means can be: surveys experiments both surveys and experiments Question 2 If all the experimental units are identical (ex: clones), you will set up the study as: CRD Block Design Question 3 a 2 sample t-test still has which normality assumption(s)? The population is normal or n is greater than 30 both populations are normal or both sample sizes are greater than 30 Question 4 When you block by some variable in a block...
This Quiz: 22 pts possit Use the standard normal distribution or the t-distribution to construct a...
This Quiz: 22 pts possit Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 40 people, the mean body mass index (BMI) was 26.9 and the standard deviation was 6.03. O A. Use a normal distribution because the sample is random, the population is normal, and is known O B. Use a...
We use the t distribution to construct a confidence interval for the population mean when the...
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find tα/2,df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) tα/2,df a. A 90% confidence level and a sample of 25 observations. b. A 95% confidence level and a sample of 25 observations.
In comparing two population means, an unpaired test provides more precise results than a paired test...
In comparing two population means, an unpaired test provides more precise results than a paired test because the unpaired test uses two independent samples while the paired test uses a single sample. True O False Question 2 1 pts When comparing two population means, if the variations which are unique to each population are very small compared to the variations which are common to both populations, it is reasonable to assume that the population standard deviations are not equal. O...
A normal distribution is approximated as a Student t distribution when the population standard deviation is unknown. Select one: True on O False
Comparing the means of two
independent population when the population variances are known and
unknownSuppose you conduct a study and intend to use a hypothesis test to compare the means of two independent populations. Your null hypothesis is that the two means are equal. That is, \(\mathrm{H}_{0}: \mu_{1}=\mu_{2}\), or equivalently, \(\mathrm{H}_{0}: \mu_{1}-\mu_{2}=0\). Following is a table of the information you gather. Assume the populations from which your samples are drawn are both normally distributed.Sample SizeSample MeanSample VarianceSample 1n_(1)=41bar(x)_(1)=14.3s_(1)^(2)=67.24Sample 2n_(2)=21bar(x)_(2)=13.6s_(2)^(2)=46.24
10. A normal population with an unknown variance has a mean of 20. Is one likely to obtain a random sample of size 9 from this population with a mean of 24 and a standard deviation of 4.1? If not what conclusion would you draw. Here are some integrals you may find helpful, where h(t) is the probability distribution function for a t-distribution with 8 degrees of freedom h(t)dt = ht) dt = h(t) dt 0.919 0.653 0.983
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