1. A) as the probability of cars being passing inspected is independent, the probability of my car passing inspection = 0.75 * 0.75 + 0.75 * 0.25 = 0.75
B) probability of my car not passing inspection = 1-0.75 = 0.25
C) probability that both cars pass = 0.75*0.75 = 0.5625
D) probability atleast one car passes = 0.75*0.75 + 0.75*0.25 + 0.25*0.75 = 0.9375
2) probability atleast one of them is defective = 1- probability none is defective = 1-0.98^4 = 0.0776394
Ukted Odwolanis Korespondenga RecencaWidok Pomoc P Powiedz mi co chcesz zrobi Fuedamentals of Quantitative Methods Part...
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