Calculate AH® for the following: rxn CH4(8) + Cl2(g) → CCl4(!) + HCl(g) [unbalanced] -139 kJ/mol...
Calculate AH® for the following: rxn CH4(g) + Cl2(g) → CCI_(1) + HCl(g) (unbalanced] NH (CH4()] = -74.87 kJ/mol AH (CC14(8)] =-96.0 kJ/mol AHCC140] =-139 kJ/mol AH [HCI(g)] = -92.31 kJ/mol AH [HCl(aq)] = -167.46 kJ/mol 1 - 121.0 kJ/mol kJ
Enter your answer in the provided box. Calculate AH for the following: rxn CH )+Cl2)-CCL)+ HCIg) [unbalanced] AH [CH (g)]=-74.87 kJ/mol f AH [CCI(g)]-96.0 kJ/mol f AH [CCI () -139 kJ/mol f AH HClg)] = -92.31 kJ/mol f AH, [HCl(aq)]=-167.46 kJmol AH, [CIg))= 121.0 kJmol kJ
3 attempts left Check my work Enter your answer in the provided box Calculate AH nxn for the following: points eBook CH4(%) + Ch) CC14() + HCl() (unbalanced] Ask Print References AH ICH,®) =-74.87 kJ/mol AH CCu(e) = -96.0 kJ/mol AH (CC140) = -139 kJ/mol AH (HCI@)] = -92.31 kJ/mol AH (HCl(aq)] = -167.46 kJ/mol AH (C1(2)) = 121.0 kJ/mol Prev 8 of 15 H N
Part A Use the information provided to determine AH°rxn for the following reaction: AHⓇ CH4(9) + 4 Cl2(g) → CCl4(g) + 4 AH°rxn = (kJ/mol) HCl(9) CH4(9) -75 CCl4(g) -96 HCl(g) -92 +79 kJ O -389 kJ 0 -113 kJ O +113 kJ O -71 kJ Submit Request Answer
6-8 Using the table below, calculate the AH rxn for each of the following equations. Selected Standard Enthalpies of Formation at 25° C (298K) AH (kJ/mol) (kJ/mol Formula AH 0 Silver 92.3 Agis) AgC(3) 0 1270 218 Formula AH (kJ/mol Formula Calcium Ca(s) CI (9) Ca(s) 635.1 HC (G) Caco (s)-1206.9 Hydrogen Hig) Carbon C(graphite) 0 H (9) C(diamond) 1.9 Nitrogen COL) -1105 N19) CO(g) -393.5 NH,(g CH_(9) 74.9 NO(9) CH,OHI) -238.6 Oxygen HỎNG) 133 O.) CS.) 87.9 O (9)...
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
82. Calculate A Hex for the reaction. CH4(8) + 4 C12(8) — CCl4(8) + 4 HCl(8) Use the following reactions and given AH's: C(s) + 2 H2(8) — CH4(8) AH = - 74.6 kJ. C(s) + 2 C12(8) - CĊ14(8) AH = -95.7 kJ X2 H2(8) + Cl2(8) —> 2HCl(8) AH = -92.3 kJ_x2 x 2 X2
Time Remai Question 4 Part A xn for the following reaction: 샌。f (kJ/mol) CH4(g) + 4 Cl2(g) → CCl4(g) + 4 HCl(g) dH'm-? CH4(g)-75 CCl4(g)-96 HCI(g)-92 O -389 kJ O +113 k O -71 kJ +79 kJ -113 kJ Submit My Answers Give Up
calculate Δh0 ulate AHo (in kJ/mol) for the reaction: B2H6(g)+6 Cl2(g)2 BCls(g)+6 HCl(g) ven the following data: BCI5(g)+3 H2O(I) H3BO:(g)+3 HCl(g) AH° = -112.5 kJ/mol B2H&(g) + 6 H2O(1) 2 H3BO:(g) + 6 H2(g)AH°= -493.4 kJ/mol AHOC(HCI, g) -92.3 kJ/mol
1. A degreasing agent, tetrachloroethylene, is produced in the reaction CH4(g) +4 HCl(g) +2 02(g) → C2C14(1) + 4H2O(1) AH° (kJ/mol): 52.26 -92.31 - 285.8 a) determine AH°for CCl4(1) AH' - 878.5 kJ a) AH° for C,CL(1) = b) How much heat (kJ) would be evolved when 7.5 kg of CH4(g) reacts completely (with stoichiometric amounts of HCl and O2)? b) heat, do = c) Using the equation for work done by/on the system; w=-P AV, calculate the amount of...