82. Calculate A Hex for the reaction. CH4(8) + 4 C12(8) — CCl4(8) + 4 HCl(8)...
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
1. How much heat is required at constant pressure to melt 1 mole of ice at -25 C to steam at 125° C? boiling point 100c melting point 0.000'C specific heat capacities are gas(steam) 2.08, liquid 4.184 solid (ice) 2.11. All in units of JigC AH(100°C) 40.7 kJ/mol AHu (0.000°C)-6.01 kJ/mol 2. Calculate AHrxn for the reaction: CH4(g)4 Cl2(g) -CC4(g) 4 HCl (g) + Use the following reactions and given AH's: CH4(g) AH =-74.6 kJ 2 H2(g) C(s) C(s)2 Cl2(g)...
Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and their AH values: | C(s) + C(s) + H2(g) + Express the enthalpy in kilojoules to one decimal place. 2H2 (g) 2Cl2(g) Cl2(g) + CH4(g), + CCL(g), + 2HCl(g), AH = -74.6 kJ AH = -95.7 kJ AH = -184.6 kJ %AM * o aj ? AH,,n= Submit Request Answer
Calculate Δ Hrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔH values: C(s)C(s)H2(g)+++2H2(g)2Cl2(g)Cl2(g)→→→CH4(g),CCl4(g),2HCl(g),ΔH=−74.6 kJΔH=−95.7 kJΔH=−184.6 kJ
Hi, can someone please explain in steps how they got the answer? Calculate Δ Hrm for the following reaction CH4(g) + 4C12 (g)CCL4 (g) +4HCl(g) given these reactions and their ΔΗ values: C(s) C(s) H2(g) + + + 2H2(g) 2C12(g) Cl2 (g) CH4 (g), CC14 (g), 2HCl(g), ΔΗ--74.6 kJ ΔΗ--95.7 kJ ΔΗ--184.6 kJ Express the enthalpy in kiloioules to one decimal place
Calculate ΔHrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔH′s. C(s)+2H2(g)→CH4(g) ΔH=−74.6kJ C(s)+2Cl2(g)→CCl4(g) ΔH=−95.7kJ H2(g)+Cl2(g)→2HCl(g) ΔH=−184.6kJ
Calculate AH® for the following: rxn CH4(8) + Cl2(g) → CCl4(!) + HCl(g) [unbalanced] -139 kJ/mol AH (CH4®= -74.87 kJ/mol a CCl4@)) = -96.0 kJ/mol AHCC140] =-139 kJ/mol AH [HCI@)) =-92.31 kJ/mol AH [HCl(aq)] =-167.46 kJ/mol Ahº [C1()] = 121.0 kJ/mol
10. Calculate ∆Hrxn for the reaction: CH4(g) + 4Cl2 → CCl4(g) + 4HCl(g) Given that: C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) ∆H = -74.6kJ ∆H = -95.7kJ ∆H = -92.3kJ
Gen Chem I Fa17 York, Exam 2 Show all work, include units as appropriate 1. Use the given standard enthalpies of formation to calculate AH° for the following reaction: CH4(9) + 4C4;() --> CC14(g) + 4HCl(3) Species AH', kJ/mol CH4(g) -74.6 Cl2(g) CCL(3) -95.7 HCl(9) -92.3 0
The overall reaction to produce chloroform from methane is CH4(g) + 3Cl2(g) ---> CHCl3(l) + 3HCl(g). Use the following intermediate reactions to calculate the enthalpy of the reaction, Hrxn. 1/2 H2(g) + 1/2 Cl2(g) ---> HCl(g) Hrxn = -92.3 kj C(s) + 2H2(g) ----> CH4(g) Hrxn = -74.8 kj C(s) + 1/2 H2(g) + 3/2 Cl2(g) ----> CHCl3(l) Hrxn = -134.5 kj