Calculate Δ Hrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔH values: C(s)C(s)H2(g)+++2H2(g)2Cl2(g)Cl2(g)→→→CH4(g),CCl4(g),2HCl(g),ΔH=−74.6 kJΔH=−95.7 kJΔH=−184.6 kJ
Calculate Δ Hrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔH values: C(s)C(s)H2(g)+++2H2(g)2Cl2(g)Cl2(g)→→→CH4(g),CCl4(g),2HCl(g),ΔH=−74.6...
10. Calculate ∆Hrxn for the reaction: CH4(g) + 4Cl2 → CCl4(g) + 4HCl(g) Given that: C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) ∆H = -74.6kJ ∆H = -95.7kJ ∆H = -92.3kJ
Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and their AH values: | C(s) + C(s) + H2(g) + Express the enthalpy in kilojoules to one decimal place. 2H2 (g) 2Cl2(g) Cl2(g) + CH4(g), + CCL(g), + 2HCl(g), AH = -74.6 kJ AH = -95.7 kJ AH = -184.6 kJ %AM * o aj ? AH,,n= Submit Request Answer
Calculate ΔHrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔH′s. C(s)+2H2(g)→CH4(g) ΔH=−74.6kJ C(s)+2Cl2(g)→CCl4(g) ΔH=−95.7kJ H2(g)+Cl2(g)→2HCl(g) ΔH=−184.6kJ
Calculate ΔrH for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔrH's. C(s)+2H2(g)→CH4(g)ΔrH=−74.6kJmol−1C(s)+2Cl2(g)→CCl4(g)ΔrH=−95.7kJmol−1H2(g)+Cl2(g)→2HCl(g)ΔrH=−92.3kJmol−1
A) Calculate ?Hrxn for the following reaction: CaO(s)+CO2(g)?CaCO3(s) Use the following reactions and given ?H values: Ca(s)+CO2(g)+12O2(g)?CaCO3(s), ?H= -812.8 kJ 2Ca(s)+O2(g)?2CaO(s), ?H= -1269.8 kJ B) Calculate ? Hrxn for the following reaction: CH4(g)+4Cl2(g)?CCl4(g)+4HCl(g) given these reactions and their ?H values: C(s)+2H2(g) ---> CH4(g), ? H=-74.6kJ C(s)+2Cl2(g) ---> CCl4(g), ? H=-95.7kL H2(g)+Cl2----> 2HCl(g), ? H=-184.6kJ
Hi, can someone please explain in steps how they got the answer? Calculate Δ Hrm for the following reaction CH4(g) + 4C12 (g)CCL4 (g) +4HCl(g) given these reactions and their ΔΗ values: C(s) C(s) H2(g) + + + 2H2(g) 2C12(g) Cl2 (g) CH4 (g), CC14 (g), 2HCl(g), ΔΗ--74.6 kJ ΔΗ--95.7 kJ ΔΗ--184.6 kJ Express the enthalpy in kiloioules to one decimal place
For the reaction CH4 + 4Cl2 CCl4 + 4HCl, how many grams of Cl2 are needed to make 55.2 g of CCl4?
A) A 9.55−g sample of a piece of diamond at 185 oC was placed in a container containing water at 87.0 oC. If the final temperature of the mixture is 91.5 oC, what is the mass of the mixture?The specific heat capacity of diamond and water are 0.52 J g−1 oC−1 and 4.184 J g−1 oC−1 respectively. Question options: A) 50.1 g B) 125 g C) 24.7 g D) 34.2 g B)Calculate the enthalpy for the reaction:CH4 + 4Cl2 →...
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
Consider the reaction at 298 K. C(graphite)+2 H 2 (g)⟶ CH 4 (g)Δ?°=−74.6 kJ C(graphite)+2H2(g)⟶CH4(g)ΔH°=−74.6 kJ Calculate the quantities. Delta Ssys=_______ J/K Delata Ssurr =_______ J/K