For the reaction CH4 + 4Cl2 CCl4 + 4HCl, how many grams of Cl2 are needed to make 55.2 g of CCl4?

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Chyt 40 ccly+tHel I Solution: 4 moles of ch form 1 mole of cela Amount of cola fornedo 55.29 Molar Mass of ccl = 153.82 g/mol

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