Question

a)

consider the following reaction

CH₄​ +4Cl₂ = CCl₄+ 4HCl

what mass of CCl₄​ is formed by the reaction of 4.80g of methane with an excess of chlorine? and why

b) Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 = 4NO + 6H2O

What mass of NO can be produced from 7.76 g of NH3? and why?

Answer 1

a)
number of moles of methane reacted = mass of methane / molar mass of methane
= 4.80 / 16
= 0.3 mol

1 mol of CH4 forms 1 moles of CCl4

so,
moles of CCl4 formed = 0.30 mol

mass of CCl4 = number of moles * molar mass
= 0.30 mol*153.82 g/mol
=46.1 g
Answer: 46.1 g

b)
number of moles of NH3 reacted = mass of NH3 / molar mass of NH3
= 7.76 / 17
= 0.456 mol

1 mol of NH3 forms 1 moles of NO

so,
moles of NO formed = 0.456 mol

mass of NO = number of moles * molar mass
= 0.456 mol*30 g/mol
=13.7 g
Answer: 13.7 g