Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and thei...
Calculate Δ Hrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔH values: C(s)C(s)H2(g)+++2H2(g)2Cl2(g)Cl2(g)→→→CH4(g),CCl4(g),2HCl(g),ΔH=−74.6 kJΔH=−95.7 kJΔH=−184.6 kJ
Calculate ΔHrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔH′s. C(s)+2H2(g)→CH4(g) ΔH=−74.6kJ C(s)+2Cl2(g)→CCl4(g) ΔH=−95.7kJ H2(g)+Cl2(g)→2HCl(g) ΔH=−184.6kJ
10. Calculate ∆Hrxn for the reaction: CH4(g) + 4Cl2 → CCl4(g) + 4HCl(g) Given that: C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) ∆H = -74.6kJ ∆H = -95.7kJ ∆H = -92.3kJ
Calculate ΔrH for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔrH's. C(s)+2H2(g)→CH4(g)ΔrH=−74.6kJmol−1C(s)+2Cl2(g)→CCl4(g)ΔrH=−95.7kJmol−1H2(g)+Cl2(g)→2HCl(g)ΔrH=−92.3kJmol−1
Hi, can someone please explain in steps how they got the answer? Calculate Δ Hrm for the following reaction CH4(g) + 4C12 (g)CCL4 (g) +4HCl(g) given these reactions and their ΔΗ values: C(s) C(s) H2(g) + + + 2H2(g) 2C12(g) Cl2 (g) CH4 (g), CC14 (g), 2HCl(g), ΔΗ--74.6 kJ ΔΗ--95.7 kJ ΔΗ--184.6 kJ Express the enthalpy in kiloioules to one decimal place
A) A 9.55−g sample of a piece of diamond at 185 oC was placed in a container containing water at 87.0 oC. If the final temperature of the mixture is 91.5 oC, what is the mass of the mixture?The specific heat capacity of diamond and water are 0.52 J g−1 oC−1 and 4.184 J g−1 oC−1 respectively. Question options: A) 50.1 g B) 125 g C) 24.7 g D) 34.2 g B)Calculate the enthalpy for the reaction:CH4 + 4Cl2 →...
A) Calculate ?Hrxn for the following reaction: CaO(s)+CO2(g)?CaCO3(s) Use the following reactions and given ?H values: Ca(s)+CO2(g)+12O2(g)?CaCO3(s), ?H= -812.8 kJ 2Ca(s)+O2(g)?2CaO(s), ?H= -1269.8 kJ B) Calculate ? Hrxn for the following reaction: CH4(g)+4Cl2(g)?CCl4(g)+4HCl(g) given these reactions and their ?H values: C(s)+2H2(g) ---> CH4(g), ? H=-74.6kJ C(s)+2Cl2(g) ---> CCl4(g), ? H=-95.7kL H2(g)+Cl2----> 2HCl(g), ? H=-184.6kJ
Item 15 You may want to reference (Pages 273-276) Section 6.8 while completing this problem. Part A for the following reaction Calculate A H CH, (g)+ 4Cl (g) CCL, (g) + 4HCI(R) given these reactions and their AH values CH,(E) C(s) +2H2(g) C(s) +2Cl2(g) CCL(g), H(g) AH-74.6 kJ AH=-95.7 kJ AH-184.6 kJ Clh (x) 2HC(g), Express the enthalpy in kilojoules to one decimal place. AH kJ Request Answer Submit Provide Feedback
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
82. Calculate A Hex for the reaction. CH4(8) + 4 C12(8) — CCl4(8) + 4 HCl(8) Use the following reactions and given AH's: C(s) + 2 H2(8) — CH4(8) AH = - 74.6 kJ. C(s) + 2 C12(8) - CĊ14(8) AH = -95.7 kJ X2 H2(8) + Cl2(8) —> 2HCl(8) AH = -92.3 kJ_x2 x 2 X2