Calculate ΔrH for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔrH's. C(s)+2H2(g)→CH4(g)ΔrH=−74.6kJmol−1C(s)+2Cl2(g)→CCl4(g)ΔrH=−95.7kJmol−1H2(g)+Cl2(g)→2HCl(g)ΔrH=−92.3kJmol−1
Calculate ΔrH for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔrH's. C(s)+2H2(g)→CH4(g)ΔrH=−74.6kJmol−1C(s)+2Cl2(g)→CCl4(g)ΔrH=−95.7kJmol−1H2(g)+Cl2(g)→2HCl(g)ΔrH=−92.3kJmol−1
Calculate Δ Hrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔH values: C(s)C(s)H2(g)+++2H2(g)2Cl2(g)Cl2(g)→→→CH4(g),CCl4(g),2HCl(g),ΔH=−74.6 kJΔH=−95.7 kJΔH=−184.6 kJ
Calculate ΔHrxn for the following reaction: CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) Use the following reactions and given ΔH′s. C(s)+2H2(g)→CH4(g) ΔH=−74.6kJ C(s)+2Cl2(g)→CCl4(g) ΔH=−95.7kJ H2(g)+Cl2(g)→2HCl(g) ΔH=−184.6kJ
10. Calculate ∆Hrxn for the reaction: CH4(g) + 4Cl2 → CCl4(g) + 4HCl(g) Given that: C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) ∆H = -74.6kJ ∆H = -95.7kJ ∆H = -92.3kJ
Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and their AH values: | C(s) + C(s) + H2(g) + Express the enthalpy in kilojoules to one decimal place. 2H2 (g) 2Cl2(g) Cl2(g) + CH4(g), + CCL(g), + 2HCl(g), AH = -74.6 kJ AH = -95.7 kJ AH = -184.6 kJ %AM * o aj ? AH,,n= Submit Request Answer
A) Calculate ?Hrxn for the following reaction: CaO(s)+CO2(g)?CaCO3(s) Use the following reactions and given ?H values: Ca(s)+CO2(g)+12O2(g)?CaCO3(s), ?H= -812.8 kJ 2Ca(s)+O2(g)?2CaO(s), ?H= -1269.8 kJ B) Calculate ? Hrxn for the following reaction: CH4(g)+4Cl2(g)?CCl4(g)+4HCl(g) given these reactions and their ?H values: C(s)+2H2(g) ---> CH4(g), ? H=-74.6kJ C(s)+2Cl2(g) ---> CCl4(g), ? H=-95.7kL H2(g)+Cl2----> 2HCl(g), ? H=-184.6kJ
For the reaction CH4 + 4Cl2 CCl4 + 4HCl, how many grams of Cl2 are needed to make 55.2 g of CCl4?
a) consider the following reaction CH4 +4Cl2 = CCl4+ 4HCl what mass of CCl4 is formed by the reaction of 4.80g of methane with an excess of chlorine? and why b) Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 = 4NO + 6H2O What mass of NO can be produced from 7.76 g of NH3? and why?
Given the equilibrium constants for the following reactions: 2H2(g) + O2(g) → 2H2O(g) K1 = 3.74 x 1026 H2(g) + Cl2(g) → 2HCl(g) K2 = 9.73 x 1012 calculate the equilibrium constant for the reaction below. 4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(g)
Calculate ΔrH for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔrH's. CH4(g)+O2(g)→CH2O(g)+H2O(g), ΔrH = -284 kJmol−1 CH2O(g)+O2(g)→CO2(g)+H2O(g), ΔrH = -527 kJmol−1 H2O(l)→H2O(g), ΔrH = 44.0 kJmol−1
The industrial degreasing solvent methylene chloride,CH2Cl2, is prepared from methane by reaction with chlorine: CH4(g)+2Cl2(g)?CH2Cl2(g)+2HCl(g) Use the following data to calculate ? H? in kilojoules for the reaction: CH4(g)+Cl2(g)?CH3Cl(g)+HCl(g)?H?=?98.3kJCH3Cl(g)+Cl2(g)?CH2Cl2(g)+HCl(g)?H?=?104kJ Express your answer using three significant figures.