The overall reaction to produce chloroform from methane is CH4(g) + 3Cl2(g) ---> CHCl3(l) + 3HCl(g). Use the following intermediate reactions to calculate the enthalpy of the reaction, Hrxn.
1/2 H2(g) + 1/2 Cl2(g) ---> HCl(g) Hrxn = -92.3 kj
C(s) + 2H2(g) ----> CH4(g) Hrxn = -74.8 kj
C(s) + 1/2 H2(g) + 3/2 Cl2(g) ----> CHCl3(l) Hrxn = -134.5 kj
The overall reaction to produce chloroform from methane is CH4(g) + 3Cl2(g) ---> CHCl3(l) + 3HCl(g)....
717)Use the reactions below to calculate the standard change in enthalpy for the reaction of methane (CH4) with chlorine to form chloroform (CHC13) and hydrochloric acid: CH4(g) + 3Cl2(g) → CHCI3(g) + 3HCI(g) Reaction 1: HCI(g) → H2(g) + 2Cl2(g) AH° = +92.3 kJ Reaction 2: CH4(g) → C(s) + 2H2(g) AH° = +74.8 kJ Reaction 3: C(s) + 3H2(g) + 3/2Cl2(g) →CHCl3(g) AH° = -103.1 kJ x a. +270.2 kl b. +248.6 kJ PC. +64.0 kJ -120.6 kJ -305.2...
Methane and chlorine react to form chloroform and hydrogen chloride, like this: CH4(9)+3C12(g) → CHCl3(9)+3HCl(9) The reaction is exothermic. Suppose a mixture of CH4, C12, CHCl3 and HCl has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. perturbation change in composition shift in equilibrium O to the...
5. Given the data below, what is AHⓇ for the following reaction? CH4(g) + 3Cl2(g) → CHCl3(g) + 3HCl(g) AHOICH4(9)] = -75 kJ/mol AHOICHCl3(9)] = -103 kJ/mol AH HCl(9)] = -92 kJ/mol A-304 kJ B-120 kJ C +322 kJ D +120 kJ E none of these
please explain each step in clear writing.
Chloroform (CHCI3) is formed from methane and chlorine in the following reaction: CH4 (g)3C12 (g)3HC1(g)+CHCI3 (g) Calculate A, Ho, the enthalpy change for this reaction, using the standard molar enthalpy change of formation of CHCI3 (g), AfH° = -103.1 kJ mol1, and the standard enthalpy changes for the following reactions: CH4 (g)202 (g)2H2O (e) CO2 (g) AH°=-890.4 kJ mol-1 2HC1(g) H2 (g)Cl2 (g) A,.H +184.6 kJ mol1 C(graphite)O2 (g)CO2 (g) A H°=-393.5 kJ...
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g) Δ?1=−912.0 kJ HCl(g)⟶HCl(aq) Δ?2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) Δ?3=−1845.0 kJ MCl3(s)⟶MCl3(aq) Δ?4=−295.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s) Δ?=?kJ
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)Δ?1=−909.0 kJ HCl(g)⟶HCl(aq) Δ?2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) Δ?3=−1845.0 kJ MCl3(s)⟶MCl3(aq) Δ?4=−398.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s)
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)Δ?1=−924.0 kJ2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)ΔH1=−924.0 kJ HCl(g)⟶HCl(aq) Δ?2=−74.8 kJHCl(g)⟶HCl(aq) ΔH2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) Δ?3=−1845.0 kJH2(g)+Cl2(g)⟶2HCl(g) ΔH3=−1845.0 kJ MCl3(s)⟶MCl3(aq) Δ?4=−123.0 kJMCl3(s)⟶MCl3(aq) ΔH4=−123.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s)
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)ΔH1=−600.0 kJ HCl(g)⟶HCl(aq) ΔH2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) ΔH3=−1845.0 kJ MCl3(s)⟶MCl3(aq) ΔH4=−215.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s) ΔH= kJ