717)Use the reactions below to calculate the standard change in enthalpy for the reaction of methane...
The overall reaction to produce chloroform from methane is CH4(g) + 3Cl2(g) ---> CHCl3(l) + 3HCl(g). Use the following intermediate reactions to calculate the enthalpy of the reaction, Hrxn. 1/2 H2(g) + 1/2 Cl2(g) ---> HCl(g) Hrxn = -92.3 kj C(s) + 2H2(g) ----> CH4(g) Hrxn = -74.8 kj C(s) + 1/2 H2(g) + 3/2 Cl2(g) ----> CHCl3(l) Hrxn = -134.5 kj
please explain each step in clear writing. Chloroform (CHCI3) is formed from methane and chlorine in the following reaction: CH4 (g)3C12 (g)3HC1(g)+CHCI3 (g) Calculate A, Ho, the enthalpy change for this reaction, using the standard molar enthalpy change of formation of CHCI3 (g), AfH° = -103.1 kJ mol1, and the standard enthalpy changes for the following reactions: CH4 (g)202 (g)2H2O (e) CO2 (g) AH°=-890.4 kJ mol-1 2HC1(g) H2 (g)Cl2 (g) A,.H +184.6 kJ mol1 C(graphite)O2 (g)CO2 (g) A H°=-393.5 kJ...
3. Calculate the standard enthalpy change (AHº) for the combustion of methane given the following data: AH° = -232.4 kJ CH4(g) + O2(g) → CH2O(g) + H20 (g) CH20 (g) + O2(g) → CO2(g) + H2O(g) AH° = -343.5 kJ 3. Calculate the standard enthalpy change (AHº) for the combustion of methane given the following data: AH° = -232.4 kJ CH4(g) + O2(g) → CH2O(g) + H20 (g) CH20 (g) + O2(g) → CO2(g) + H2O(g) AH° = -343.5 kJ...
Part A Calculate A H xn for the following reaction: CHA(g) + 4Cl2(g) → CCl4(g) + 4HCl(g) given these reactions and their AH values: | C(s) + C(s) + H2(g) + Express the enthalpy in kilojoules to one decimal place. 2H2 (g) 2Cl2(g) Cl2(g) + CH4(g), + CCL(g), + 2HCl(g), AH = -74.6 kJ AH = -95.7 kJ AH = -184.6 kJ %AM * o aj ? AH,,n= Submit Request Answer
find the enthalpy change H for this reaction: CH4(g) + Cl2--> CCl4(g)+HCl Using the following Equations: C(s)+H2(g)-->CH4 H= -74.6 kJ C(s) + Cl2(g)--> CCl4 H=-95.7 kJ H2(g)+Cl2(g)--> HCl H=-92.3 kJ
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
11. It is possible to measure the enthalpy change for the two reactions below. Reaction equation Standard Enthalpy of reaction (kJ/mol.rxn) a. CH4 (g) + 2O2 (g) → CO2(g) + 2 H20 (g) b. CH3OH (g) + 3/2 02(g) → CO2(g) + 2H20 (8) -802.4 -676 Using Hess's Law, determine the enthalpy change for the reaction below. C. CH4 (8) + % O2 (8) > CH3OH (g)
A scientist measures the standard enthalpy change for the following reaction to be - 87.7 kJ : 2HBr(g) + Cl2(g)— 2HCl(g) + Bra(s) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(g) is kJ/mol CH4() + H2O(g)_3H2(g) + CO(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O() is kJ/mol Given the standard enthalpy changes for...
Using standard heats of formation, calculate the standard enthalpy change for the following reaction 2HBr(g) H2(g) + Br2() ANSWER kJ Submit Answer Retry Entire Group 2 more group attempts remaining Given the standard enthalpy changes for the following two reactions: (1) Zn(s)+ Cl2(g) ZnCl2(s) AH° = -415.0 kJ (2) Fe(s) + Cl2(g) FeCl2(s) AH° = -341.8 kJ what is the standard enthalpy change for the reaction: (3) Zn(s) + FeCl(s) AH° ? ZnCl2(s) + Fe(s) kJ Given the standard enthalpy...
Find the change in enthalpy for the reaction below, given the following reactions and change in enthalpy values: C2H2(g)+ 5/202(g)-2CO2(g) + H2O(g) ΔΗ ? Use: C2H6(g) → C2H2(g) + 2H2(g) ΔΗ : 283.5 kJ H29) 1/2029) H20(g) AH--213.7 kJ 2CO2(g) + 3H2O(g)-C2H6(g) + 7/2O2(g) ΔΗ = 849 kJ