According to Hess's law , whether the reaction takes place in a single step or multiple steps , the enthalpy change of the reaction is the sum of enthalpies of each step.
11. It is possible to measure the enthalpy change for the two reactions below. Reaction equation...
1. Using the reactions given below please calculate the change in enthalpy (delta H) for the stated reaction. Stated Reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) delta H = ?! Given Reactions & Enthalpy Changes: 2 Fe(s) + 3/2 02(g) → Fe2O3(s) 2 Fels) * delta H = -824.2 kJ delta H = -282.7 kJ CO(g) + 4 02(g) → CO2(g) 2. Using the reactions given below please calculate the change in enthalpy (delta H) for...
Find the change in enthalpy for the reaction below, given the following reactions and change in enthalpy values: C2H2(g)+ 5/202(g)-2CO2(g) + H2O(g) ΔΗ ? Use: C2H6(g) → C2H2(g) + 2H2(g) ΔΗ : 283.5 kJ H29) 1/2029) H20(g) AH--213.7 kJ 2CO2(g) + 3H2O(g)-C2H6(g) + 7/2O2(g) ΔΗ = 849 kJ
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Use the following information and hess's law to find the enthalpy change for the reaction C(g) + O2(g) => CO2(g) reaction 1: 2CO(g) + O2(g) => 2CO2(g) ΔH = -566 kj reaction 2: 2C(g) + O2(g) => 2CO(g) ΔH = -1655 kj
3. Calculate the standard enthalpy change (AHº) for the combustion of methane given the following data: AH° = -232.4 kJ CH4(g) + O2(g) → CH2O(g) + H20 (g) CH20 (g) + O2(g) → CO2(g) + H2O(g) AH° = -343.5 kJ 3. Calculate the standard enthalpy change (AHº) for the combustion of methane given the following data: AH° = -232.4 kJ CH4(g) + O2(g) → CH2O(g) + H20 (g) CH20 (g) + O2(g) → CO2(g) + H2O(g) AH° = -343.5 kJ...
- + ~ [ Fit to page 1 11. Hess's Law - Calculate the enthalpy for the following reaction (20 pts) 11.1. NzH4 (1) ► N; (g) + 2H; (g)AH = ? Consider that N2H4 (1) +02 → N(g) + H20 (g), AH = -543.2 kJ 2H2(g) + O2 → H20 (g), AH = -241.8 kJ
Use the enthalpies for the given reactions to compute the standard enthalpy change (ΔH°) for the reaction: 6 C (s) + 7 H2(g) → C6H14 (l) ΔHrxn = ? C6H14 (l)+19/2O2 (g)→6CO2(g)+ 7H2O(g). ΔH=–3505.8kJ C(s) + O2 (g) → CO2(g) ΔH=–393.5kJ H2(g) + 1/2 O2(g) → H2O(g). ΔH = – 242.0 kJ
Using Hess's Law, determine the enthalpy change of the following reaction. CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) C(s) + O2(g) --> CO2(g) AH = -393.5 kJ/mol S(s) + O2(g) --> SO2(g) AH = -296.8 kJ/mol C(s) + 25(s) --> CS2(8) AH = +87.9 kJ/mol -899.2 kJ O-778.2 kJ -602.4 kJ - 1075.0 kJ
10. Given the thermochemical data below, what is the change in enthalpy when 10.0 g of H, are reacted? N; (g) + 3H2(g) → 2NH, (g): AH = -91.2 kJ (A) -452 kJ (B) +452 kJ (C) -151 kJ (D) -1357 kJ 11. Which of the following is NOT a state function? 1. Heat 2. Change in enthalpy 3. Change in internal energy 4. Change in pressure (A) 1 only (B) 2 only (C) 2 and 3 (D) 1 and...